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Bas_tet [7]
3 years ago
15

Please draw and label two perpendicular line segments KL and MN

Mathematics
2 answers:
muminat3 years ago
6 0
So draw a cross! One line segment is KL and the other Mn
Elina [12.6K]3 years ago
5 0
____________|m__________l
k l
l
l
ln
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Steven recently won $1 in the scratch-n-play lotto. His banker,
kolbaska11 [484]

Answer:

101.00

Step-by-step explanation:

Given:

P=principal=$1

r=rate=1%=0.01

n=number of periods=12

t=time=1

Compound Interest (A)=P(1+r/n)^nt

=$1(1+0.01/12)^12×1

=$1(1+0.00083)^12

=$1(1.00083)^12

=$1(1.0100055)

=$1.0100055

Approximately

101.00

5 0
3 years ago
What is the missing constant term in the perfect square that starts with x2+18xx^2+18xx2+18xx, squared, plus, 18, x ?
katrin2010 [14]

Answer:

81

Step-by-step explanation:

Given the expression: x^2+18x

To make it a perfect square, we follow the following steps.

Divide the coefficient of x by 2

  • Coefficient of x=18, 18/2=9

Square It

  • 9 X 9=81

Add it to the expression

  • x^2+18x+81

This is written as a perfect square as: (x+9)^2

The constant term required therefore is 81.

4 0
3 years ago
Read 2 more answers
How to solve y in -(y+9)=10
Allisa [31]

Answer:


Step-by-step explanation:

- (y+9) = 10


Multiply through by -1 gives us


y+9 = -10


Subtract 9 from both sides


y = -19


That's your answer.


If you work it through it satisfies the equation.


That is:


- (-19 +9) = 10


-(-10) = 10


10 = 10


Boo ya!

5 0
3 years ago
Assume the general population gets an average of 7 hours of sleep per night. You randomly select 45 college students and survey
tekilochka [14]

Answer:

a) ii. This is a left-tailed test.

b) -1.59

c) -1.301

d) i. reject null hypothesis

e) Option i) The data supports the claim that college students get less sleep than the general population.

Step-by-step explanation:

We are given the following in the question:  

Population mean, μ = 7 hours

Sample mean, \bar{x} = 6.87 hours

Sample size, n = 45

Alpha, α = 0.10

Sample standard deviation, s =  0.55 hours

First, we design the null and the alternate hypothesis

H_{0}: \mu = 7\text{ hours}\\H_A: \mu < 7\text{ hours}

a) We use one-tailed(left) t test to perform this hypothesis.

b) Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Putting all the values, we have

t_{stat} = \displaystyle\frac{6.87 - 7}{\frac{0.55}{\sqrt{45}} } =-1.59

c) Now,

t_{critical} \text{ at 0.10 level of significance, 44 degree of freedom } = -1.301

Since,                    

t_{stat} < t_{critical}

d) We fail to accept the null hypothesis and reject it.

We accept the alternate hypothesis and conclude that  mean number of hours of sleep for all college students is less than 7 hours.

e) Option i) The data supports the claim that college students get less sleep than the general population.

8 0
3 years ago
Please solve for w, p=21+2w
sp2606 [1]

Answer:

w = (p - 21)/2

Step-by-step explanation:

Rearrange the equation so that it is equal to w.

p = 21 + 2w

p - 21 = (21 + 2w) - 21

p - 21 = 2w

(p - 21)/2 = (2w)/2

(p - 21)/2 = w

w = (p - 21)/2

3 0
3 years ago
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