Gloria went to the mall and spent 50 minutes shopping
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Answer:
Part A: f(x) = 4·x² - 7·x-15 = (x - 3)·(4·x + 5)
Part B: The x-intercepts are x = 3 and -1.25 #
Part C: As x approaches ∞, y approaches ∞, as x approaches -∞, y approaches ∞
Part D: The graph is a u-shaped quadratic equation graph passing though the x-intercept points -1.25 and 3 on the x-axis and the y-intercept point -15 on the y-axis. Both sides of the symmetrical graph curve extending to infinity
Step-by-step explanation:
The function 4·x² - 7·x-15
To factorize the expression, we have at the 0 factors;
Where;
a = 4, b = -7, c -15, substituting gives;
Which gives;
(x - 3)·(x + 1.25) = (x - 3)·(4·x + 5)
f(x) = 4·x² - 7·x-15 = (x - 3)·(4·x + 5)
Part B: The x-intercepts are the point where y = 0, which are x = 3 and -1.25 as shown above
Part C: As x approaches ∞, y approaches ∞, as x approaches -∞, y approaches ∞
Part D: With the the nature of the function as y approaches ∞ and -∞ the graph is a u-shaped graph of a quadratic equation passing though the points -1.25 and 3 on the x-axis and the point -15 on the y-axis.
The given equation is
The slope of the given line is 6.
It is important to know that parallel lines have the same slopes, so the slope of the new line is 6.
Now, we use the point-slope formula to find the new line
Let's replace the point (-4,7) and the slope 6.