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Scrat [10]
3 years ago
11

Project 13.3: Assessing Risk Management According to the FFIEC Information Security InfoBase Handbook ( Appendix A ), the initia

l step in a regulatory Information Technology Examination is to interview management and review examination information to identify changes to the technology infrastructure, new products and services, or organizational structure.1. Explain how changes in network topology, system configuration, or business processes might increase the institution’s information security–related risk. Provide examples.2. Explain how new products or services delivered to either internal or external users might increase the institution’s might increase the institution’s information security–related risk. Provide examples.3. Explain how loss or addition of key personnel, key management changes, or internal reorganizations might increase the institution’s information security–related risk. Provide examples.
Engineering
1 answer:
Rashid [163]3 years ago
5 0

Answer:

1. Changes in network topology or system configuration might bring security-related challenges. For example, adopting a new system configuration which is low in cost but also very new in the Industry might be vulnerable to the existing security.

2. New products or Services which are delivered to either the Internal/External users might be prone to security issues.

Let say a product 'A' has been launched by a company 'X' and for testing purpose it has been given to the internal users. Now as this product 'A' is a product of 'X' itself it will be allowed to carry in the official premises and if some user tries to hack this product and can make the product potentially harmful w.r.t security.

3. Consider a scenario where there is a change in management & team, the team members which were thoroughly responsible for Security kinds of stuff are dissolved into different teams. Also new members are hired for the team. Now, since the new members will need some time to get adapted to the Business As Usual things there are high chances of a security level not maintained as it was earlier by the old guys. This could be due to undocumented things in the organization or due to lack of Knowledge Transfer to the new joinees.

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The following is a list of metals and alloys:
viktelen [127]

Answer:

A) Gray cast iron

B) Aluminum

C) Titanium alloy

D) Tool steel

E) Titanium alloy

F) magnesium

G) Tungsten

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3 years ago
Why is it reasonable to say that no system is 100% efficient?​
Virty [35]

Generally, frictional losses are more predominant for the machines being not 100% efficient. This friction leads to the loss of energy in the form of heat, into the surroundings. Some of the supplied energy may be utilised to change the entropy (measure of randomness of the particles) of the system.

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3 years ago
The fracture strength of glass may be increased by etching away a thin surface layer. It is believed that the etching may alter
Korvikt [17]

Answer:

the ratio of the etched to the original crack tip radius is 30.24

Explanation:

Given the data in the question;

we determine the initial fracture stress using the following expression;

(σf)₁ = 2(σ₀)₁ [ α₁/(p_t)₁ ]^{1/2 ----- let this be equation 1

where; (σ₀)₁ is the initial fracture strength

(p_t)₁ is the original crack tip radius

α₁ is the original crack length.

first, we determine the final crack length;

α₂ = α₁ - 16% of α₁

α₂ = α₁ - ( 0.16 × α₁)

α₂ = α₁ - 0.16α₁

α₂ = 0.84α₁

next, we calculate the final fracture stress;

the fracture strength is increased by a factor of 6;

(σ₀)₂ = 6( σ₀ )₁

Now, expression for the final fracture stress

(σf)₂ = 2(σ₀)₂ [ α₂/(p_t)₂ ]^{1/2 ------- let this be equation 2

where (p_t)₂ is the etched crack tip radius

value of fracture stress of glass is constant

Now, we substitute 2(σ₀)₁ [ α₁/(p_t)₁ ]^{1/2 from equation for (σf)₂  in equation 2.

0.84α₁ for α₂.

6( σ₀ )₁ for (σ₀)₂.

∴

2(σ₀)₁ [ α₁/(p_t)₁ ]^{1/2  = 2(6( σ₀ )₁) [ 0.84α₁/(p_t)₂ ]^{1/2  

divide both sides by 2(σ₀)₁

[ α₁/(p_t)₁ ]^{1/2  =  6 [ 0.84α₁/(p_t)₂ ]^{1/2

[ 1/(p_t)₁ ]^{1/2  =  6 [ 0.84/(p_t)₂ ]^{1/2

[ 1/(p_t)₁ ]  =  36 [ 0.84/(p_t)₂ ]

1 / (p_t)₁ = 30.24 / (p_t)₂

(p_t)₂ = 30.24(p_t)₁

(p_t)₂/(p_t)₁ = 30.24

Therefore, the ratio of the etched to the original crack tip radius is 30.24

6 0
3 years ago
What are the disadvantages of having a liquid cooled engine?
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3 years ago
Why does teachers grade things that are not due yet​
pav-90 [236]
I think because if you’ve already turned it in they might as well grade asap instead of waiting
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3 years ago
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