Answer:
The volume of water needed to be removed = 4301100 lbs/ [ 62.43 × 27] = 2551.66.
Explanation:
The first thing to do right now is to determine the weight of soil solids. This can be gotten below as:
The weight of soil solids = 1 × 118 × 27 = <em>3186 lbs. </em>
Also, there is the need to determine the value of the water that we have and the one that is needed. This is calculated below as:
The weight of water needed = 3186 × 6% = 191.16 lbs.
The water available = 3186 × 7% = 223.02%.
The next thing to determine is the value for the total BCY of available of soil.
Thus, the total BCY of available of soil = [ 3186 + 223.02 ]/ 2800 × 135000 = 3409.02/ 2800 = 1.217551 BCY × 135000 = 164,363.46 BCY.
The last thing to do here is to determine the value for the weight and volume of water to be removed.
The weight of water to be removed = [ 223.02 lbs - 191.16 lbs] × 135,000 = 4301100 lbs
The volume of water needed to be removed = 4301100 lbs/ [ 62.43 × 27] = 2551.66.
Answer:
The stress level at which fracture will occur for a critical internal crack length of 6.2mm is 135.78MPa
Explanation:
Given data;
Let,
critical stress required for initiating crack propagation Cc = 112MPa
plain strain fracture toughness = 27.0MPa
surface length of the crack = a
dimensionless parameter = Y.
Half length of the internal crack, a = length of surface crack/2 = 8.8/2 = 4.4mm = 4.4*10-³m
Also for 6.2mm length of surface crack;
Half length of the internal crack = length of surface crack/2 = 6.2/2 = 3.1mm = 3.1*10-³m
The dimensionless parameter
Cc = Kic/(Y*√pia*a)
Y = Kic/(Cc*√pia*a)
Y = 27/(112*√pia*4.4*10-³)
Y = 2.05
Now,
Cc = Kic/(Y*√pia*a)
Cc = 27/(2.05*√pia*3.1*10-³)
Cc = 135.78MPa
The stress level at which fracture will occur for a critical internal crack length of 6.2mm is 135.78MPa
For more understanding, I have provided an attachment to the solution.
Answer:
- B. Precipitation require the diffusional activation energy plus an additional energy to form the precipitate.
Explanation:
Precipitation is the creation of a solid from a solution. When the reaction occurs in a liquid solution, the solid formed is called the precipitate.
The formation of a precipitate indicates the occurrence of a chemical reaction.
Precipitation of carbide requires alot of energy which the diffusion activational energy alone cannot achieve and this was calculated to be 225.6 kJ/mol.
Answer:
t = 1456.8 sec
Explanation:
given data:
contant k = 2.60*10^{-6}
rate of crystallization is 0.0013 s-1
rate of transformation is given by
use specifies value to solve
it is ime required for 50% tranformation
Avrami equation is given by
n = 1.88
second degree of recrystalization may be determine by rearranging original avrami equation
for 90%completion
t = 1456.8 sec
Answer:
The percent elongation in the length of the specimen is 42%
Explanation:
Given that:
The gage length of the original test specimen = 50 mm
The final gage length = 71 mm
The area = 206 mm²
maximum load = 162,699 N
To determine the percent elongation in %, we use the formula:
The percent elongation in the length of the specimen is 42%