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shepuryov [24]
3 years ago
13

Please help fast

Engineering
1 answer:
Vitek1552 [10]3 years ago
4 0
The balloon could not rise. The air inside would not be an lighters than the air
outside.
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After having done the hand calculation and pseudocode for a program that models inflating a spherical balloon, now implement the
vampirchik [111]

Answer:

Explanation:

CODE :

import java.util.Scanner; // required imports for the class

class Balloon { // class to run the code

public static void main(String[] args) { // driver method

Scanner in = new Scanner(System.in); // scanner class to get the data

System.out.print("Diameter: "); // message

double diameter = in.nextDouble(); // prompt

double growth = 1; // local variables

int c = 0;

while (c < 10) { // iterate over the loop

double radius = diameter / 2; // calculate the radius

double vol = ((double)4 / 3) * 3.14 * radius * radius * radius; // calculate the initial volume

diameter = growth + diameter; // update the diamter

System.out.printf("\nIncrease in the Diameter is : %.0f", growth); // message

System.out.println("\nNew Diameter is : " + diameter); // print the diameter

radius = diameter / 2; // calculate the new diameter

double growthvol = ((double)4 / 3) * 3.14 * radius * radius * radius; // calculate the new volume

System.out.printf("Increase in the Volume is : %.0f", growthvol - vol); // message

System.out.println("\nNew Volume is : " + growthvol); // message

c++; // increment the count

}

}

}

OUTPUT :

run 1 :

Diameter: 10

Increase in the Diameter is : 1

New Diameter is : 11.0

Increase in the Volume is : 173

New Volume is : 696.5566666666667

Increase in the Diameter is : 1

New Diameter is : 12.0

Increase in the Volume is : 208

New Volume is : 904.3199999999998

Increase in the Diameter is : 1

New Diameter is : 13.0

Increase in the Volume is : 245

New Volume is : 1149.7633333333333

Increase in the Diameter is : 1

New Diameter is : 14.0

Increase in the Volume is : 286

New Volume is : 1436.0266666666666

Increase in the Diameter is : 1

New Diameter is : 15.0

Increase in the Volume is : 330

New Volume is : 1766.25

Increase in the Diameter is : 1

New Diameter is : 16.0

Increase in the Volume is : 377

New Volume is : 2143.5733333333333

Increase in the Diameter is : 1

New Diameter is : 17.0

Increase in the Volume is : 428

New Volume is : 2571.1366666666668

Increase in the Diameter is : 1

New Diameter is : 18.0

Increase in the Volume is : 481

New Volume is : 3052.08

Increase in the Diameter is : 1

New Diameter is : 19.0

Increase in the Volume is : 537

New Volume is : 3589.5433333333335

Increase in the Diameter is : 1

New Diameter is : 20.0

Increase in the Volume is : 597

New Volume is : 4186.666666666667

run 2 :

Diameter: 7.5

Increase in the Diameter is : 1

New Diameter is : 8.5

Increase in the Volume is : 101

New Volume is : 321.39208333333335

Increase in the Diameter is : 1

New Diameter is : 9.5

Increase in the Volume is : 127

New Volume is : 448.6929166666667

Increase in the Diameter is : 1

New Diameter is : 10.5

Increase in the Volume is : 157

New Volume is : 605.82375

Increase in the Diameter is : 1

New Diameter is : 11.5

Increase in the Volume is : 190

New Volume is : 795.9245833333334

Increase in the Diameter is : 1

New Diameter is : 12.5

Increase in the Volume is : 226

New Volume is : 1022.1354166666666

Increase in the Diameter is : 1

New Diameter is : 13.5

Increase in the Volume is : 265

New Volume is : 1287.59625

Increase in the Diameter is : 1

New Diameter is : 14.5

Increase in the Volume is : 308

New Volume is : 1595.4470833333332

Increase in the Diameter is : 1

New Diameter is : 15.5

Increase in the Volume is : 353

New Volume is : 1948.8279166666664

Increase in the Diameter is : 1

New Diameter is : 16.5

Increase in the Volume is : 402

New Volume is : 2350.87875

Increase in the Diameter is : 1

New Diameter is : 17.5

Increase in the Volume is : 454

New Volume is : 2804.7395833333335

Description :

During the casting or the calculation of the volume and the radius the RHS needs to be casted for the numerator with the double datatype so as to clearly get the result. And that the formula is also been updated.

Hope this is helpful.

7 0
3 years ago
Let S = { p q |p, q are prime numbers greater than 0} and E = {0, −2, 2, −4, 4, −6, 6, · · · } be the set of even integers. . Pr
Finger [1]

Answer:

prove that | S | = | E | ; every element of S there is an Image on E , while not every element on E has an image on S

Explanation:

Given that S = { p q |p, q are prime numbers greater than 0}

                    E = {0, −2, 2, −4, 4, −6, 6, · · · }

To prove  by constructing a bijection from S to E

detailed  solution attached below

After the bijection :

<em>prove that | S | = | E |</em> :  every element of S there is an Image on E , while not every element on E has an image on S

∴ we can say sets E and S are infinite sets

7 0
3 years ago
Consider a cubic workpiece of rigid perfect plastic material with side length lo. The cube is deformed plastically to the shape
Taya2010 [7]

Answer:  ε₁+ε₂+ε₃ = 0

Explanation: Considering the initial and final volume to be constant which gives rise to the relation:-

                         l₀l₀l₀=l₁l₂l₃

                        \frac{lo*lo*lo}{l1*l2*l3}=1.0

                      taking natural log on both sides

                              ln(\frac{(lo*lo*lo)}{l1*l2*l3})=ln(1)

Considering the logarithmic Laws of division and multiplication :

                                ln(AB) = ln(A)+ln(B)

                                ln(A/B) = ln(A)-ln(B)

                           ln(\frac{(l1)}{lo})*ln(\frac{(l2)}{lo})*ln(\frac{(l3)}{lo}) = 0

Use the image attached to see the definition of true strain defined as

                         ln(l1/1o)= ε₁

which then proves that ε₁+ε₂+ε₃ = 0

8 0
3 years ago
Assume that the voltage applied to a load is V = 208-30° V and the current flowing through the load is I = 515° A. (a) Calcula
RoseWind [281]
Idk I just need point an you probably already solved this by now
3 0
3 years ago
Write a SELECT statement that returns these four columns:
labwork [276]

A SELECT command pulls zero or more rows from one or more database tables or views. SELECT is the most often used data manipulation language (DML) command in most applications. See the statement required below.

<h3>What is the SELECT Statement that gives the above results?</h3>

SELECT VendorName, InvoiceNumber, InvoiceDate,

InvoiceTotal - PaymentTotal - CreditTotal AS Balance

FROM Vendors JOIN Invoices

ON Vendors.VendorID = Invoices.VendorID

WHERE InvoiceTotal - PaymentTotal - CreditTotal > 0

ORDER BY VendorName;

Learn more about SELECT Statements at;

brainly.com/question/19338967
#SPJ1

3 0
2 years ago
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