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3 years ago

I really need help fast please

Mathematics

2 answers:

spin [16.1K]3 years ago

8 0

I would help you but I can't see it maybe zoom in a little closer.

enot [183]3 years ago

3 0

So what you need to do is multiply all of the lengths given together to find the volime. volume= length × width × height. To get you started, the answer to number 1 is 144 because 3×8×6 is 144.

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What is the y-intercept in the equation y = 4x - 3?

maw [93]

Answer:

-3

Step-by-step explanation:

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2 years ago

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Hellen is using 3.508 grams of copper for her science experiment. How many kilograms of copper did Hellen use for her science ex

mash [69]

Answer:

.003508 kg of copper

Step-by-step explanation:

1000 grams = 1 kg

3.508 g/1000 g = .003508 kg

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2 years ago

A baker uses chocolate with 75% cocoa for his famous cake. But his supplier delivered 100 lb of chocolate with 70% cocoa, so the

Nonamiya [84]

Answer:

213 1/3

Step-by-step explanation:

Because I know where you got this question from.

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3 years ago

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Teacher's salaries in Georgia are normally distributed with an average salary of $52,000 with a standard deviation of $12,000. W

suter [353]

Answer:

81.85%

Step-by-step explanation:

We have the following information:

mean = m = 52000

standard deviation = sd = 12000

a = 40000

b = 76000

we need to find the probability between a and b, that is:

P (a <x <b) = P (40,000 <x <76000)

P [(40000 - m) / sd <(x - m) / sd <(76000 - m) / sd]

replacing

P [(40000 - 52000) / 12000 <z <(76000 - 52000) / 12000]

P (-1 <z <2)

P (z <= -1) - P (z <= 2)

We look for this value of z, in the attached table:

0.9772 - 0.1587

P = 0.8185

In other words, the probability is 81.85%

8 0

3 years ago

Find the max and min values of f(x,y,z)=x+y-z on the sphere x^2+y^2+z^2=81

Anton [14]

Using Lagrange multipliers, we have the Lagrangian

$L(x,y,z,\lambda)=x+y-z+\lambda(x^2+y^2+z^2-81)$

with partial derivatives (set equal to 0)

$L_x=1+2\lambda x=0\implies x=-\dfrac1{2\lambda}$
$L_y=1+2\lambda y=0\implies y=-\dfrac1{2\lambda}$
$L_z=-1+2\lambda z=0\implies z=\dfrac1{2\lambda}$
$L_\lambda=x^2+y^2+z^2-81=0\implies x^2+y^2+z^2=81$

Substituting the first three equations into the fourth allows us to solve for $\lambda$ :

$x^2+y^2+z^2=\dfrac1{4\lambda^2}+\dfrac1{4\lambda^2}+\dfrac1{4\lambda^2}=81\implies\lambda=\pm\dfrac1{6\sqrt3}$

For each possible value of $\lambda$ , we get two corresponding critical points at $(\mp3\sqrt3,\mp3\sqrt3,\pm3\sqrt3)$ .

At these points, respectively, we get a maximum value of $f(3\sqrt3,3\sqrt3,-3\sqrt3)=9\sqrt3$ and a minimum value of $f(-3\sqrt3,-3\sqrt3,3\sqrt3)=-9\sqrt3$ .

5 0

3 years ago