Answer:
Fe^2+(aq) + S^2-(aq) --------> FeS(s)
Explanation:
First let us look at the molecular equation;
Na2S(aq) + Fe(NO3)2(aq) --------> FeS (s) + 2NaNO3(aq)
Now, the net ionic equation usually shows the most important reaction that took place, in this case, the formation of the FeS precipitate.
Hence, ionically;
Fe^2+(aq) + S^2-(aq) --------> FeS(s)
a pure compound because an element is untouched and is just itself
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When sulfur reacts with zinc metal is forms a compound known as zinc sulfide.
<h3>
Name of the elements</h3>
The names of the elements that make up the compound will be determined from the atomic mass of the elements.
<h3>Which element has atomic number 30</h3>
The element that atomic number of 30 is zinc and it has oxidation number of +2.
<h3>Which element has atomic number 16</h3>
The element that atomic number of 16 is sulfur and it has oxidation number of -2.
<h3>Chemical reaction between sulfur and zinc metal</h3>
Zn²⁺ + S²⁻ --------> ZnS
Thus, when sulfur reacts with zinc metal is forms a compound known as zinc sulfide.
Learn more about zinc sulfide here: brainly.com/question/20806552
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