Answer:
Explanation: Bromine, the dark red color disappears quickly as the atoms of bromine bond with the atoms of carbon in the double bond.
The quantities you have to know are the molar masses and the molecular stoichiometric ratios. The solution for this problem is as follows:
Mass Percent of Iodine = (Mass of Iodine/Mass of NaBr and KI)*100
Mass of NaBr = 1 mol NaBr * 102.89 g/mol = 102.89 g
Mass of KI = 0.3 mol KI * 166 g/mol = 49.8 g
Mass of KI = 0.3 mol KI * 1 mol I/1mol KI * 1 mol I₂/2 mol I * 253.81 g/mol = 38.07 g
Mass %I₂ = 38.07/(102.89+49.8) * 100 = <em>24.9%</em>
Answer:
One of the main functions lipids do is storing energy.
provide the building blocks for muscle tissue
Answer:
34.8 g
Explanation:
Answer:
We have the masses of two reactants, so this is a limiting reactant problem.
We will need a balanced equation with masses, moles, and molar masses of the compounds involved.
1. Gather all the information in one place with molar masses above the formulas and masses below them.
Mᵣ: 123.90 70.91 208.24
P₄ + 20Cl₂ ⟶ 4PCl₅
Mass/g: 46.0 32.0
2. Calculate the moles of each reactant
3. Calculate the moles of PCl₅ we can obtain from each reactant
From P₄:
The molar ratio is 4 mol PCl₅:4 mol P₄
From Cl₂:
The molar ratio is 4 mol PCl₅:20 mol Cl₂
4. Identify the limiting and excess reactants
The limiting reactant is chlorine, because it gives the smaller amount of PCl₅.
The excess reactant is phosphorus.
5. Mass of excess reactant
(a) Moles of P₄ reacted
The molar ratio is 1 mol P₄:20 mol Cl₂
(b) Mass of P₄ reacted
(c) Mass of P₄ remaining
Mass remaining = original mass – mass reacted = (46.0 - 11.18) g = 34.8 g P₄