Answer:
<em>3</em><em>6</em><em> </em><em>electrons.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>
Density= 1.2092 because density = mass/volume
Answer:
It might be C
Explanation:
I looked it up since I didn't remember and it said that humidity increases the more it rains
Article-
https://www.smartfog.com/how-rain-and-humidity-connected.html#:~:text=When%20it%20rains%2C%20it%20will,air%20constantly%20drawing%20the%20water.
Plz correct me if I'm wrong
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Answer:
C₇H₁₄O₂
Explanation:
From the question given above, the following data were obtained:
Mass of compound = 1.152 g
Mass of CO₂ = 2.726 g
Mass of H₂O = 1.116 g
Empirical formula =?
Next, we shall determine the mass of carbon, hydrogen and oxygen present in the compound. This can be obtained as follow:
For carbon (C):
Mass of CO₂ = 2.726 g
Molar mass of CO₂ = 12 + (2×16)
= 12 + 32
= 44 g/mol
Mass of C = 12/44 × 2.726
Mass of C = 0.743 g
For hydrogen (H):
Mass of H₂O = 1.116 g
Molar mass of H₂O = (2×1) + 16
= 2 + 16
= 18 g/mol
Mass of H = 2/18 × 1.116
Mass of H = 0.124 g
For oxygen (O):
Mass of compound = 1.152 g
Mass of C = 0.743 g
Mass of H = 0.124 g
Mass of O =?
Mass of O = (Mass of compound) – (Mass of C) + (Mass of H)
Mass of O = 1.152 – (0.743 + 0.124)
Mass of O = 1.152 – 0.867
Mass of O = 0.285 g
Finally, we shall determine the empirical formula for the compound as follow:
C = 0.743 g
H = 0.124 g
O = 0.285 g
Divide by their molar mass
C = 0.743 / 12 = 0.062
H = 0.124 / 1 = 0.124
O = 0.285 / 16 = 0.018
Divide by the smallest
C = 0.062 / 0.018 = 3.44
H = 0.124 / 0.018 = 7
O = 0.018 / 0.018 = 1
Multiply by 2 to express in whole number.
C = 3.44 × 2 = 7
H = 7 × 2 = 14
O = 1 × 2 = 2
Empirical formula => C₇H₁₄O₂
Answer:
The procedure with the simple calorimeter to compare the energy released by different fuels is described below in detail.
Explanation:
If the response delivers heat (rxn < 0), then heat is consumed by the calorimeter (calorimeter > 0), and its temperature improves. Conversely, if the response consumes heat (rxn > 0), suddenly heat is carried from the calorimeter to the arrangement (calorimeter < 0), and the temperature of the calorimeter drops.