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puteri [66]
3 years ago
14

Which ordered pairs make both inequalities true? Check all that apply.

Mathematics
2 answers:
Margaret [11]3 years ago
6 0
When an <span>inequality is true it is in the region that both are shaded, so the answer would be 1,1 and 2,2</span>
Tema [17]3 years ago
4 0

Answer: The pair (2, 2)

Step-by-step explanation:

The inequalities that we have are:

y ≥ (1/5)x + 1

y < 2x + 1

Now, let's try the options:

Notice that the pairs that make bot inequalities true are pairs that lie in the region where we have both colors (blue and orange)

Those options will be the pairs (1,3) and (2,2)

now, let's prove if those numbers work for our inequalities.

(1,3)

3 ≥ (1/5)*1 + 1 = 6/5  true

3 < 2*1 + 1 = 3 false

here we have a problem, while the pair (1,3) lies in the region, it lies exactly in the doted line of the second inequality, this means that this pair does not work for the second inequality.

now, let's test the other option.

(2, 2)

2 ≥ (1/5)*2 + 1  =7/6 true

2 < 2*2 + 1 = 5 true

the correct option is the pair (2, 2)

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3 years ago
six times a number is greater than 20 more than that number.what are the possible values of that number?
sergiy2304 [10]

Answer:

All the values greater than the number 4 are possibles values for this number:

Step-by-step explanation:

Let x is the number mentioned:

Six times a number : 6 ( x )

Twenty more than the number: 20 + x

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3 0
3 years ago
The difference between the largest share and the smallest share when 3450 yen is divided in the ratios 2:6:7
worty [1.4K]

Answer:

1150 yen

Step-by-step explanation:

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The smallest share is two

So 2×230 = 460 yen

Biggest share is Seven

So 7×230 = 1610 yen

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4 0
4 years ago
Determine the value of y, if x is 3.<br> y = | x | + 5<br> Answer:
dlinn [17]

Answer:

y=8

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