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puteri [66]
3 years ago
14

Which ordered pairs make both inequalities true? Check all that apply.

Mathematics
2 answers:
Margaret [11]3 years ago
6 0
When an <span>inequality is true it is in the region that both are shaded, so the answer would be 1,1 and 2,2</span>
Tema [17]3 years ago
4 0

Answer: The pair (2, 2)

Step-by-step explanation:

The inequalities that we have are:

y ≥ (1/5)x + 1

y < 2x + 1

Now, let's try the options:

Notice that the pairs that make bot inequalities true are pairs that lie in the region where we have both colors (blue and orange)

Those options will be the pairs (1,3) and (2,2)

now, let's prove if those numbers work for our inequalities.

(1,3)

3 ≥ (1/5)*1 + 1 = 6/5  true

3 < 2*1 + 1 = 3 false

here we have a problem, while the pair (1,3) lies in the region, it lies exactly in the doted line of the second inequality, this means that this pair does not work for the second inequality.

now, let's test the other option.

(2, 2)

2 ≥ (1/5)*2 + 1  =7/6 true

2 < 2*2 + 1 = 5 true

the correct option is the pair (2, 2)

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Help please! (no one was answering it in physics and i really need help)
aivan3 [116]

Let v_0 be the cat's speed just as it leaves the edge of the table. Then taking the point 1.3 m below the edge of the table to be the origin, the cat's horizontal position at time t is given by

x(t)=v_0t

and its height is

y(t)=1.3\,\mathrm m-gt^2

where g is 9.8 m/s^2, the magnitude of the acceleration due to gravity.

The time it takes for the cat to hit the ground is t with

0=1.3\,\mathrm m-gt^2\implies t=\sqrt{\dfrac{1.3\,\rm m}g}\approx0.36\,\mathrm s

(Unfortunately, this doesn't match any of the given options...)

The cat lands 0.75 m away (horizontally) from the edge of the table, so that its speed v_0 was

0.75\,\mathrm m=v_0(0.36\,\mathrm s)\implies v_0\approx2.08\dfrac{\rm m}{\rm s}

(Again, not one of the answer choices...)

I'm guessing there's either a typo in the question or answers.

6 0
3 years ago
1. Digite na
SOVA2 [1]

Answer:

ne diyorsunuz anlamadım gitti

ingilizce bilen ben ingilizce bilmiyorum diyorum ama bosver

3 0
2 years ago
Two cards are drawn with replacement, one after the other, and the outcomes recorded. What is the probability that at least one
babymother [125]

Answer:

The probability is 0.231

Step-by-step explanation:

In this question, we are tasked with calculating the probability that out of two cards drawn with replacement from a pack of cards , at least one of the two is a face card.

In a standard pack of cards, there are 52 cards.

Now let’s calculate the number of face cards we have.

There are 12 face cards in a pack of cards. There are 4 of each of Jack, Queen or King

The probability of drawing a face card is 12/52 = 3/13

Now, we want to calculate the probability of at least one of the cards drawn are face cards.

Mathematically, what we are needing to calculate is

Probability of drawing a single face card or probability of the two being a face card

Now let’s calculate.

The probability of the first card drawn being a face card is 3/13. The probability of the second card not being a face card will be 1-3/13 = 10/13

The joint probability under this first set of condition will be 3/13 * 10/13 = 30/169

Now, for the second condition, here we are considering that both cards drawn are face cards. What we have is 3/13 * 3/13 = 9/169

Now in probabilities, whenever we are having the statement or, we add the probabilities together

Thus, the probability here would be 30/169 + 9/169 = 39/169 = 3/13

In decimal this will be 0.231

8 0
2 years ago
Find the midpoint of the line segment joining the points r(1,4) s(-3,7)
skad [1K]
Formula for mid point.
(x1/2+x2/2 , y1/2+ y2/2)

Mid point=
(1/2+ (-3)/2 , 4/2+ 7/2)
(-2/2 , 11/2)
(-1, 5.5)
5 0
3 years ago
Read 2 more answers
What is 2 1/5 + 1 1/5
Reptile [31]

Answer:

3.4

Step-by-step explanation:

divide it all into a calculator

7 0
3 years ago
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