Question

How many moles of helium atoms are there in 2.4 x 10^24? need equation

Answer 1

Mol = # atoms ÷ Avagadaro's number (6.02×10^23)

mol = 2.4×10^24 ÷ 6.02×10^23
mol = 3.986 mol

Answer 2

Answer:

$n_{He}=3.99molHe$

Explanation:

Hello,

To compute the required moles, we consider the Avogadro's number relationship for 1 mole of atoms as shown below:

$n_{He}=2.4x10^{24}atomsHe*\frac{1mol He}{6.022x10^{23}atoms He}\\n_{He}=3.99molHe$

Best regards.