All of the following are examples of physical properties EXCEPT

Classify each chemical compound listed in the table below.

prisoha [69]

Answer:

Please find attached the table of classification of the chemical compounds, created with Microsoft Word

Explanation:

The given compounds are;

H₂SO₃ is an acid which is known as sulfurous acid

When SO₂ is added to water, we have;

SO₂ + H₂O ⇄ HSO₃ + H⁺

Therefore, H₂SO₃ is ionic

2) HI which is known as hydrogen iodide, dissolves in water as follows

HI (g) + H₂O (l) ⇄ H₃O⁺(aq) + I⁻(aq)

Therefore, HI is able to donate hydrogen ions therefore, it is both acidic and ionic

3) KI is a salt of the alkali metal, potassium, and iodine which is a group 7 element such that it formed by the transfer of electrons from potassium to iodine making it an ionic compound

KI forms a slightly alkaline solution

4) NaClO₃ comprises of the ionic combination of sodium and chlorate ions which dissolves in water as follows;

NaClO₃ → Na⁺(aq) + ClO₃⁻(aq)

Therefore, NaClO₃ is ionic

NaClO₃ is also a strong oxidizing agent, making a Br∅nsted acid

we have;

Sulfurous acid (also Sulfuric(IV) acid, Sulphuric acid (UK), Sulphuric(IV) acid (UK)) is the chemical compound with the formula H2SO3. There is no evidence that sulfurous acid exists in solution, but the molecule has been detected in the gas phase.[1] The conjugate bases of this elusive acid are, however, common anions, bisulfite (or hydrogen sulfite) and sulfite.

4 0

3 years ago

The wax in a burning candle can be described by both physical and chemical properties. What are the physical properties of the w

dimaraw [331]

Answer:

The change of state of wax from solid to liquid and liquid to vapors is a physical change.

Explanation:

Physical Change

The changes that occur only due to change in shape or form but their chemical or internal composition remain unchanged.

These changes were reversible.

They have same chemical property.

These changes can be observed with naked eye.

Chemical:

The changes, that occur due to change in the composition of a substance and result in a different compound is known as chemical change.

These changes are irreversible .

These changes occur due to chemical reactions.

These may not be observed with naked eye

Example

When a candle is burned, the both physical and chemical changes occur.

The solid wax is melted into the liquid and than liquid is evaporated into vapor form. It is a physical change because just the state of mater is changed. When vapors of wax are react with oxygen in air and form carbon dioxide and ash it is a chemical change which can not be reversed.

8 0

3 years ago

How many kilowatt-hours of electricity are used to produce 3.00 kg of magnesium in theelectrolysis of molten MgCl2 with an appli

Llana [10]

Answer:

There is 29.8 kilowatt hours needed.

Explanation:

Step 1: Data given

Mass of Magnesium = 3.00 kg

Molar mass of magnesium = 24.31 g/mol

Applied emf = 4.50 V (= 4.50 J/C)

Step 2: Calculate moles of Magnesium

Moles = Mass Mg / Molar mass Mg

Moles Mg = 3000 grams / 24.31 g/mol

Moles Mg = 123.4 moles

Step 3: Calculate how many electrons are needed to produce the magnesium.

The ionic equation for the reduction of Mg^2+ :

Mg^2+ + 2e^- → Mg

Every mole of Mg requires 2 mol of electrons.

For 123.4 mol of Mg, we have 246.8 mol of electrons.

Step 3: Find how many coulombs are involved.

The Faraday constant = 96500 couloumbs

1 mole of electrons is 96500 coulombs.

246.8 mol of electrons need 2.38 *10^7 Coulombs

Step 4: Calculate kilowatt-hours of electricity needed

2.38 * 10^7 C * 4.5 J/C = 10.7 * 10^7 J

10.7 * 10^7 J * ( 1 kW-h-/ 3.6*10^6 J ) = 29.8 kWh

There is 29.8 kilowatt hours needed.

5 0

3 years ago

What is the molar mass of water in the hydrate? FeSO4 • 7H2O

Rainbow [258]

M=7M(H₂O)

M=7*18.015 g/mol = 126.105 g/mol

5 0

4 years ago

15.0 g of cream at 10.0 ℃ are added to an insulated cup containing 150.0 g of coffee at 78.6 °C. Calculate the equilibrium tempe

elena-14-01-66 [18.8K]

Answer:

The equilibrium temperature of the coffee is 72.4 °C

Explanation:

Step 1: Data given

Mass of cream = 15.0 grams

Temperature of the cream = 10.0°C

Mass of the coffee = 150.0 grams

Temperature of the coffee = 78.6 °C

C = respective specific heat of the substances( same as water) = 4.184 J/g°C

Step 2: Calculate the equilibrium temperature

m(cream)*C*(T2-T1) = -m(coffee)*c*(T2-T1)

15.0 g* 4.184 J/g°C *(T2 - 10.0°C) = -150.0g *4.184 J/g°C*(T2-78.6°C)

62.76T2 - 627.6 = -627.6T2 + 49329.36

690.36T2 = 49956.96

T2 = 72.4 °C

The equilibrium temperature of the coffee is 72.4 °C

7 0

3 years ago