Answer:
a. First order.
b. 
c. 
d. ![[A]=0.111M](https://tex.z-dn.net/?f=%5BA%5D%3D0.111M)
Explanation:
Hello.
a. In this case since the slope is in s⁻¹ we can infer that the lineal form of the rate law is:
![ln[A]=-kt+ln[A]_0](https://tex.z-dn.net/?f=ln%5BA%5D%3D-kt%2Bln%5BA%5D_0)
Which is also:
It means that the reaction is first-order as slope equals the negative of the rate constant which also has units of first-oder reaction.
b. Since the slope is −3.7 x 10−3 s−1 the rate constant is:
c. For first-order reactions, the half-life is:
d. In this case, since the integrated first-order rate law is:
![[A]=[A]_0exp(-kt)](https://tex.z-dn.net/?f=%5BA%5D%3D%5BA%5D_0exp%28-kt%29)
The concentration once 220 seconds have passed is:
![[A]=0.250Mexp(-3.7x10^{-3}s^{-1}*220s)\\\\](https://tex.z-dn.net/?f=%5BA%5D%3D0.250Mexp%28-3.7x10%5E%7B-3%7Ds%5E%7B-1%7D%2A220s%29%5C%5C%5C%5C)
Regards.
The amount of KCl that would be formed will be 478.8 grams
<h3>Stoichiometric calculations</h3>
From the equation of the reaction, the mole ratio of K to 
is 2:1.
Mole of 309 g potassium = 309/39 = 7.92 moles
Mole of 228 g Cl2 = 228/71 = 3.21 moles
Thus, potassium is in excess while Cl2 is limiting.
Mole ratio of Cl2 and KCl = 1:2
Equivalent mole of KCl = 3.21 x 2 = 6.42 moles
Mass of 6.42 moles KCl = 6.42 x 74.55 = 478.8 grams
More on stoichiometric calculations can be found here: brainly.com/question/27287858
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Answer:12 cm^3 becoz as per Gay-Lussac law
H2+Cl2---. 2HCl thus ratio is 1:1:2
Explanation:
