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3 years ago

Two angles have a common vertex but no common side. How can you tell whether the angles are vertical angles?

Mathematics

1 answer:

pentagon [3]3 years ago

8 0

Vertical angles is an X but that's how you tell if they're vertical angles

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Solving Quadratic Equations using the Square Root Property

Afina-wow [57]

Answer:

$x = -2$ or $x = -5$

Step-by-step explanation:

You need to complete the square before you can take the square root of both sides.

$x^2 + 7x + 10 = 0$

Subtract 10 from both sides.

$x^2 + 7x = -10$

To complete the square, you need to add the square of half of the x-term coefficient to both sides.

The x-term coefficient is 7. Half of that is 7/2. Square it to get 49/4. Now we add 49/4 to both sides of the equation.

$x^2 + 7x + \dfrac{49}{4} = -10 + \dfrac{49}{4}$

$(x + \dfrac{7}{2})^2 = -\dfrac{40}{4} + \dfrac{49}{4}$

$(x + \dfrac{7}{2})^2 = \dfrac{9}{4}$

Now we use the square root property, if

$x^2 = k$ , then

$x = \pm \sqrt{k}$

$x + \dfrac{7}{2} = \pm \sqrt{\dfrac{9}{4}}$

$x + \dfrac{7}{2} = \pm \dfrac{3}{2}$

$x + \dfrac{7}{2} = \dfrac{3}{2}$ or $x + \dfrac{7}{2} = -\dfrac{3}{2}$

$x = -\dfrac{4}{2}$ or $x = -\dfrac{10}{2}$

$x = -2$ or $x = -5$

5 0

3 years ago

In a right triangle, <A and <B are acute. Find the value of sin A, when tan A = 8/15

finlep [7]

Answer:sinA=8/17

Step-by-step explanation:

Using Pythagoras principle

x=√(15^2+8^2)

x=√(15x15+8x8)

x=√(225+64)

x=√(289)

x=17

SinA=opposite/hypothenus

SinA=8/17

3 0

3 years ago

Average rate of change

Ganezh [65]

Answer:

The average rate of change in that space would be 12.

Step-by-step explanation:

To find this, use the two ordered pairs (-1, 3) and (1, 27) in the slope formula.

m(slope) = (y2 - y1)/(x2 - x1)

m = (27 - 3)/(1 - -1)

m = 24/2

m = 12

7 0

3 years ago

What is the slope of the line?

sineoko [7]

Answer:

3/4

Step-by-step explanation:

You can do this two different ways. Both include picking two points where the line crosses a corner. I'm using (0,-1) and (4,2). Now here you can either use

Slope= $\frac{Rise}{Run}$

or $\frac{y2-y1}{x2-x1}$

If you use the first one start at point (0,-1) and go to point (4,2) and count how many it goes up (rise) and then put that over how many it goes to the right (run).

If you use the second one then plug in the numbers.

y2=second y point

y1=first y point

x2=second x point

x1=first x point

$\frac{2-(-1)}{4-0}$ Now just solve.

$\frac{3}{4}$

4 0

3 years ago

(-5, -1) and (1,9)<br> Answer:

xxMikexx [17]

Answer:

m = 5/3

Step-by-step explanation:

7 0

3 years ago