How many moles of glucose (C6H12O6) are in 1.5 liters of a 4.5 M C6H12O6 solution?
2 answers:
Answer: 6.75 moles
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.
Given;
Molarity = 4.5 M
n= moles of solute (glucose) = ?
= volume of solution in L = 1.5 L
Putting in the values we get,
Thus moles of glucose are 6.75 moles in 1.5 liters of a 4.5 M solution.
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Answer:
1) 0,081 ft/s
2) 0,746 lb/s
Explanation:
The relation between flow and velocity of a fluid is given by:
Q=Av
where:
- Q, flow [ft3/s]
- A, cross section of the pipe [ft2]
- v, velocity of the fluid [ft/s]
1)
To convert our data to appropiate units, we use the following convertion factors:
1 ft=12 inches
1 ft3=7,48 gallons
1 minute=60 seconds
So,
As the pipe has a circular section, we use A=πd^2/4:
Finally:
Q=vA......................v=Q/A
2)
The following formula is used to calculate the specific gravity of a material:
SG = ρ / ρW
where:
- SG = specific gravity,
- ρ = density of the material [lb/ft3]
- ρW = density of water [lb/ft3] = 62.4 lbs/ft3
then:
ρ = SG*ρW = 1,49* 62,4 lb/ft3 = 93 lb/ft3
To calculate the mass flow, we just use the density of the chloroform in lb/ft3 to relate mass and volume: