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2 years ago

How many moles of glucose (C6H12O6) are in 1.5 liters of a 4.5 M C6H12O6 solution?

Chemistry

2 answers:

miv72 [106K]2 years ago

6 0

Answer: 6.75 moles

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

$Molarity=\frac{n}{V_s}$

Given;

Molarity = 4.5 M

n= moles of solute (glucose) = ?

$V_s$ = volume of solution in L = 1.5 L

Putting in the values we get,

$4.5=\frac{n}{1.5}$

$n=6.75moles$

Thus moles of glucose are 6.75 moles in 1.5 liters of a 4.5 M $C_6H_{12}O_6$ solution.

zepelin [54]2 years ago

3 0

For the answer to the question above asking, h<span>ow many moles of glucose (C6H12O6) are in 1.5 liters of a 4.5 M C6H12O6 solution?
The answer to your question is the the third one among the given choices which is 6.8 mol.
</span><span>moles glucose = 1.5 x 4.5 = 6.8 </span>

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Calculate the mole fraction of the total ions in an aqueous solution prepared by dissolving 0.400 moles of CaI2 in 850.0 g of wa

Evgesh-ka [11]

Answer:

0.00840

Explanation:

The computation of the mole fraction is as follow:

As we know that

Molar mass = Number of grams ÷ number of moles

number of moles = Number of grams ÷ molar mass

Given that

Number of moles of CaI2 = 0.400

And, Molar mass of water = 18.0 g/mol

Now Number of moles of water is

= 850.0 g ÷ 18.0 g/mol

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And, Total number of moles is

= 0.400 + 47.22

= 47.62

So, Molar fraction of CaI2 is

= 0.400 ÷ 47.62

= 0.00840

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3 years ago

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Answer:

5.25 moles.

Explanation:

The decomposition reaction of NaN₃ is as follows :

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