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ololo11 [35]
3 years ago
14

An ice freezer behind a restaurant has a freon leak, releasing 41.60 g of C2H2F3Cl into the air every week. If the leak is not f

ixed, how many kilograms of fluorine will be released into the air over 6 months? Assume there are 4 weeks in a month. mass of fluorine leaked over 6 months:
Chemistry
1 answer:
zlopas [31]3 years ago
5 0
Weeks = 6 x 4 = 24
Mass leak rate of freon = 41.60 g/week
Mass leak rate of fluorine
Fluorine mass in Freon
= —————————————- X leak rate
M.M. Of Freon

19 x 3
——— X 41.60 = 20.010 gm/week
118.5

Total leaked in 6 months

= 24 x 20.010 = 480.24 gm = 0.480 Kg
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Many scientists have been involved in the development of the theory of the structure of
Genrish500 [490]

Answer:

bohr descirbed the atomic structure and found that electrons travel in separate orbits around the nucleus. jj thomson created the plum pudding model.

7 0
2 years ago
The absolute temperature of a gas is increased four times while maintaining a constant volume. What happens
poizon [28]

Answer:

<u>It increases by a factor of four</u>

Explanation:

Boyle's Law : At constant temperature , the volume of fixed mass of a gas is inversely proportional to its pressure.

pV = K.......(1)

pV = constant

Charles law : The volume of the gas is directly proportional to temperature at constant pressure.

V = KT

or V/T = K = constant ....(2)

Applying equation (1) and (2)

\frac{PV}{T}=K

\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}

According to question ,

T2 = 4 (T1)

V2 = V1

Put the value of T2 and V2 , The P2 can be calculated,

\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{1}}{4T_{1}}

V1 and V1 cancel each other

T1 and T1 cancel each other

We get,

P1=\frac{P2}{4}

or

P2 = 4 P1

So pressure increased by the factor of four

5 0
3 years ago
Calculate the solubility of mn(oh)2 in grams per liter when buffered at ph=7.0. assume that buffer capacity is not exhausted
Vanyuwa [196]
When PH + POH = 14 
∴ POH = 14 -7 = 7

when POH = -㏒[OH-]

          7    = -㏒ [OH-]
∴[OH-] = 10^-7

by using ICE table:

           Mn(OH)2(s) ⇄  Mn2+ (aq)  + 2OH-(aq)
initial                              0                     10^-7
change                           +X                      +2X
Equ                                 X                  (10^-7 + 2X)

when Ksp = [Mn2+][OH-]^2

when Ksp of Mn(OH)2 = 4.6 x 10^-14

by substitution:

4.6 x 10^-14 = X*(10^-7+2X)^2  by solving this equation for X

∴ X =2.3 x 10-5 M

∴ The solubility of Mn(OH)2 in grams per liter (when the molar mass of Mn(OH)2 = 88.953 g/mol
= 2.3 x10^-5 moles/L * 88.953 g/mol

= 0.002 g/ L
3 0
3 years ago
Read 2 more answers
Critical Thinking Challenge: A student has a part time
mina [271]

Answer:

6⅔ shifts

Explanation:

From the question given:

A shift = 4 hours

Pay = $8.25 per hour

Next, we shall determine the number of hours that will result in a pay of $220. This can be obtained as follow:

$8.25 = 1 hour

Therefore,

$220 = $220 × 1 hour / $8.25

$220 = 220/8.25 hours.

$220 = 80/3 hours

$220 = 26⅔ hours

Therefore, it will take 26⅔ hours to receive a pay of $220.

Finally, we shall determine the number of shifts in 26⅔ hours. This can be obtained as follow:

4 hours = 1 shift

Therefore,

26⅔ hours = 26⅔ ÷ 4

26⅔ hours = 80/3 × 1/4

26⅔ hours = 80/12

26⅔ hours = 20/3

26⅔ hours = 6⅔ shifts

Therefore, she will work 6⅔ shifts in order to receive a pay of $220

6 0
3 years ago
Which pair of elements would most likely form a covalent bond
denpristay [2]

Answer:

Nonmetals and nonmetals tend to form covalent bonds.

or

P and S

Explanation:

5 0
2 years ago
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