Question

An ice freezer behind a restaurant has a freon leak, releasing 41.60 g of C2H2F3Cl into the air every week. If the leak is not fixed, how many kilograms of fluorine will be released into the air over 6 months? Assume there are 4 weeks in a month. mass of fluorine leaked over 6 months:

Answer 1

Weeks = 6 x 4 = 24
Mass leak rate of freon = 41.60 g/week
Mass leak rate of fluorine
Fluorine mass in Freon
= —————————————- X leak rate
M.M. Of Freon

19 x 3
——— X 41.60 = 20.010 gm/week
118.5

Total leaked in 6 months

= 24 x 20.010 = 480.24 gm = 0.480 Kg