Answer:
19.9 mol
Explanation:
Use <em>Avogadro’s number</em> to convert formula units of CaI₂ to moles of CaI₂.
1 mol CaI₂ ≡ 6.022 × 10²³ formula units CaI₂
Moles of CaI₂ = 1.20 × 10²⁵ × (1 /6.022 × 10²³)
Moles of CaI₂ = 19.9 mol
You would have to look for the mass of the sample and the volume of the sample.
Answer:
A
Explanation:
because it loses 2 electrons
Types of Bonds can be predicted by calculating the
difference in electronegativity.
If, Electronegativity difference is,
Less
than 0.4 then it is Non Polar Covalent Bond
Between 0.4 and 1.7 then it is Polar Covalent Bond
Greater than 1.7 then it is Ionic
For Br₂;
E.N of Bromine = 2.96
E.N of Bromine = 2.96
________
E.N Difference
0.00 (Non Polar Covalent Bond)
For MgS;
E.N of Sulfur = 2.58
E.N of Magnesium = 1.31
________
E.N Difference 1.27 (Ionic Bond)
For SO₂;
E.N of Oxygen = 3.44
E.N of Sulfur = 2.58
________
E.N Difference 0.86 (Polar Covalent Bond)
For KF;
E.N of Fluorine = 3.98
E.N of Potassium = 0.82
________
E.N Difference 3.16 (Ionic Bond)
Result: The Bonds in Br₂ and SO₂ are Covalent in Nature.
