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2 years ago

An electrical field has:

Physics

2 answers:

Darya [45]2 years ago

8 0

Answer:

magnitude and direction

Explanation:

Dominik [7]2 years ago

4 0

Answer:

C) magnitude and direction

Explanation:

Since force is a vector, the electric field too is a vector quantity

and a vector quantity have both direction and magnitude!

✌️:)

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Any help would be great! Thank you x Giving brainliest answer xoxo

garri49 [273]

Answer:

A vacuum would have been created. I hope this helps have a great day

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2 years ago

A person is listening to a tone of 500 Hz sitting from a distance of 450 m from the source of the sound. What is the time interv

VladimirAG [237]

Answer:

ΔX = λ = 0.68 m

Explanation:

Wave speed is related to wavelength and frequency by the equation

v = λ f

where the speed of sound is 340 m / s

λ = v / f

λ = 340/500

λ = 0.68 m

this is the wavelength, it is the minimum distance for which the wave epitates its movement, which is equal to the distance between two consecutive compressions of the sound

ΔX = λ = 0.68 m

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3 years ago

I need DISPLACEMENT please. I have Average speed, i need Displacement.

Lapatulllka [165]

Define displacement and I'll help you

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3 years ago

Individuals with favorable traits are ________ in an environment

77julia77 [94]

Succesful is correct.

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2 years ago

A vacuum cleaner produces sound with a measured sound level of 75.0 dB. (a) What is the intensity of this sound in W/m2? W/m2 (b

jonny [76]

Answer:

Part a)

$I = 3.16 \times 10^{-5} W/m^2$

Part b)

$P_o = 0.162 Pa$

Explanation:

Part a)

Level of sound = 75 dB

now we know that

$L = 10 Log\frac{I}{I_0}$

here we know that

$I_0 = 10^{-12} W/m^2$

now we have

$75 = 10 Log(\frac{I}{10^{-12}})$

$I = 3.16 \times 10^{-5} W/m^2$

Part b)

Intensity of sound wave is given as

$I = \frac{1}{2}\rho A^2\omega^2 c$

here we know that

$A = \frac{P_o}{Bk}$

so we have

$I = \frac{1}{2}\rho(\frac{P_o}{Bk})^2\omega^2 c$

$I = \frac{1}{2}\rho P_o^2 \frac{c^3}{B^2}$

now we know

$\rho = 1.2 kg/m^3$

$c = 340 m/s$

$B = 1.4 \times 10^5 Pa$

now we have

$3.16 \times 10^{-5} = \frac{1}{2}(1.2)P_o^2\frac{340^3}{(1.4\times 10^5)^2}$

$P_o = 0.162 Pa$

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2 years ago