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Alexxandr [17]
3 years ago
6

forty eight students were divided into two groups for a field trip. The first group is three times as large as the second group

less twelve. How many students were in each group?
Mathematics
1 answer:
NISA [10]3 years ago
4 0
I believe the first group would have 36 and the second group would have 12
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Hello plz solve this question whoever solves best gets brainlest and points any links will be reported thank you
Drupady [299]

Answer:

D is correct

Step-by-step explanation:

4 0
2 years ago
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A town's population is 14,280, and it is increasing by 160 people every year. A nearby town has a population of 24,000, and it i
fgiga [73]

Answer:

27 years

Step-by-step explanation:

Given that :

Town A:

Initial population = 14280

Rate = increase by 160 per year

Let t = time in years

Population is thus :

14280 + 160t - - - (1)

Town B:

Initial population = 24000

Rate = decrease by 200 per year

P = 24000 - 200t - - - (2)

Equate both equations :

14280 + 160t = 24000 - 200t

160t + 200t = 24000 - 14280

360t = 9720

t = 9720 / 360

t = 27

In 27 years

7 0
2 years ago
A company’s profit in dollars is modeled by the equation p(x) = –0.5x2 + 100x, where x represents the number of units sold.
serg [7]

Answers:

a. The company needs to sell 100 units to reach the maxmum profit.

b. The company's maximum profit is $5,000.

Solution:

a. How many unit does the company need to sell to reach the maximum profit?

p(x)=-0.5x^2+100x

This is a quadratic equation, and its graph is a parabola vertical (because the veriable "x" is square). Comparing with the general form:

p(x)=ax^2+bx+c; a=-0.5, b=100, c=0

a=-0.5<0 (negative), then the parabola opens downward, and it has a maximimun value (maximum profit) at its vertex.

We can find the abscissa of the vertex (units that the company needs to sell to reach the maximum profit using the following formula:

x=-b/(2a)

Replacing b by 100 and a by -0.5 in the formula above:

x=-100/[2(-0.5)]

x=-100/(-1)

x=100

The company needs to sell 100 units to reach the maximum profit.


b. What's the company's maximum profit?  

To determine the maximum profit we substitute the value of "x" obrained in part "a" in the quadratic equation:

x=100→p(100)=-0.5(100)^2+100(100)

p(100)=-0.5(10,000)+10,000

p(100)=-5,000+10,000

p(100)=5,000

The company's maximum profit is $5,000.

6 0
2 years ago
Mar 12: 3
erastovalidia [21]

Answer:

  • Mar 18: 125
  • Mar 19: 318
  • Mar 20: 743
  • Mar 25: 15,070

Step-by-step explanation:

The six seemingly arbitrary points have no common difference or ratio, so cannot be modeled by a linear or exponential function.

The differences of the differences are not constant at any level, so the only polynomial model is 5th-degree. It is ...

  (6n^5 -95n^4 +600n^3 -1825n^2 +2814n -1320)/60

where n = days after Mar 11. (Mar 12 corresponds to n=1.) The domain is n ≥ 1.

____

The 5th-degree polynomial increases very fast, but not as fast as an exponential function would.

The values for Mar 12 through Mar 25 are ...

  3, 8, 11, 16, 25, 50, 125, 318, 743, 1572, 3047, 5492, 9325, 15070

6 0
3 years ago
Find the following differences:
Lyrx [107]

Answer:

1- 0.123

2- 0.0745

3- 0.9706

5 0
2 years ago
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