Answer:
10.96
Explanation:
<em>A solution is prepared at 25 °C that is initially 0.14 M in diethylamine, a weak base with Kb = 1.3 × 10⁻³, and 0.20 M in diethylammonium chloride. Calculate the pH of the solution. Round your answer to 2 decimal places.</em>
Step 1: Calculate the pOH of the solution
Diethylamine is a weak base and diethylammonium (from diethylammonium chloride) its conjugate acid. Thus, they form a buffer system. We can calculate the pOH of this buffer system using the Henderson-Hasselbach's equation.
pOH = pKb + log [acid]/[base]
pOH = -log 1.3 × 10⁻³ + log 0.20 M/0.14 M
pOH = 3.04
Step 2: Calculate the pH of the solution
We will use the following expression.
pH + pOH = 14
pH = 14 - pOH = 14 -3.04 = 10.96
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Answer:
<em>Dissolving a solid in liquid, such as table salt in water, is a physical change because only the state of the matter has changed. Physical changes can often be reversed. Allowing the water to evaporate will return the salt to a solid state.</em>
Explanation: Please give me brainliest.
The experiment should theoretically yield 3.50 g of the product.
However during the experiment it can yield only 3.10 g of the product.
actual yield is lesser than the theoretical yield, therefore we need to find the percentage yield.
Percentage yield can be calculated using the following equation
Percent yield = 3.10 g / 3.50 g x 100% = 88.6%
1 atm = 760 mmHg
29.8 mmHg / 760 mmHg * 1atm = 0.039 atm
