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3 years ago

PLEASE PLEASE HELP!

Chemistry

1 answer:

valentinak56 [21]3 years ago

8 0

Answer: The number of grams of $H_2$ in 1620 mL is 1.44 g

Explanation:

According to ideal gas equation:

$PV=nRT$

P = pressure of gas = 1 atm (at STP)

V = Volume of gas = 1620 ml = 1.62 L (1L=1000ml)

n = number of moles = ?

R = gas constant = $0.0821Latm/Kmol$

T =temperature = $273K$

$n=\frac{PV}{RT}$

$n=\frac{1atm\times 16.2L}{0.0821Latm/K mol\times 273K}=0.72moles$

Mass of hydrogen = $moles\times {\text {Molar mass}}=0.72mol\times 2g/mol=1.44g$

The number of grams of $H_2$ in 1620 mL is 1.44 g

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