Answer:
I love you and i'm proud of you :)
Answer:
About 99.7% of births would be expected to occur within 51 days of the mean pregnancy length
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviation of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Standard deviation = 17.
About what percentage of births would be expected to occur within 51 days of the mean pregnancy length?
51/17 = 3.
So, within 3 standard deviations of the mean.
About 99.7% of births would be expected to occur within 51 days of the mean pregnancy length
The formula to calculate the z-score of a certain value is:
z = (x - (mean))/(standard deviation)
In this example, the x-value is 450, the S.D. is 100, and the mean is 500.
So, substitute these values into the formula.
z = (450-(500))/100
z=-50/100
z=-0.5
Therefore, the z-score is -0.5.
<span>There would be 2 groups. The greatest amount in each pile is 2 cards</span>
the first team won 10%over of is game then the next team won5%over it team
