A) 5000 m²
b) A(x) = x(200 -2x)
c) 0 < x < 100
Step-by-step explanation:
b) The remaining fence, after the two sides of length x are fenced, is 200-2x. That is the length of the side parallel to the building. The product of the lengths parallel and perpendicular to the building is the area of the playground:
A(x) = x(200 -2x)
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a) A(50) = 50(200 -2·50) = 50·100 = 5000 . . . . m²
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c) The equation makes no sense if either length (x or 200-2x) is negative, so a reasonable domain is (0, 100). For x=0 or x=100, the playground area is zero, so we're not concerned with those cases, either. Those endpoints could be included in the domain if you like.
In the bag there’s is 5 blue and only 2 green she is most likely gonna pick blue. Who would even want to know that
On an isosceles trapezoid, the two sides that are not parallel to each other will be exactly the same length. If this is true, than it would be create a symetric trapezoid. The diagonals would be the same length. The bases of any trapezoid are parallel, so this is true. The diagonals cannot possibly be perpendicular because the 2 nonparallel sides would be slanted. So, the answer is the 3rd choice.
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