Sent a picture of the solution to the problem (s).
The amount invested in the first account is $9,300 while the amount invested in the second account is $8,800.
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How do we calculate the amount invested?</h3>
Let x represents the amount invested in the first account.
Therefore, we have:
Amount invested in the second account = x - 500
Interest income from first account = 3% * x = 0.03x
Interest income from second account = 5% * (x - 500) = 0.05x - 25
Total interest income = 0.03x + 0.05x - 25 = 719
Solving for x, we have:
0.08x = 719 + 25
x = 744 / 0.08
x = $9,300
Substituting for x, we have:
Amount invested in the second account = $9,300 - $500 = $8,800
Learn more about the amount invested here: brainly.com/question/24132106.
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2a because with 18a and 20ab they both have "a" in common and they are even thus multiples of 2 leaving you with 2a(9,10b)
9+3 =12
12/4 = 3
(3)2-4(3)-3
6-12-3
-9 is the answer
Write out the expression 2 - (2x-7)^2. That's it.
But if you want to go further and remove the parentheses, first expand (2x-7)^2: (2x-7)^2 = 4x^2 - 28x + 49,
and then subtract this result from 2:
2 - (4x^2 - 28x + 49) (It's important to use parentheses here)
Now, following the distributive property of multiplication, remove the parentheses:
2 - 4x^2 + 28x - 49
Combining the constants, we get the final answer: - 4x^2 + 28x - 47
