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mash [69]
3 years ago
15

Slopes of parallel line are

Mathematics
2 answers:
ValentinkaMS [17]3 years ago
8 0

Answer:

the solution is C. identical

Step-by-step explanation:

slope of parallel lines are the same

lara [203]3 years ago
3 0

Answer:

the slopes of parallel lines are : C. identifical

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What is the slope of the line that passes through the points (-4,-4) and (9,4)
aleksandrvk [35]

Answer:

4-(-4)/9-(-4)

slope=8/13

6 0
3 years ago
An instructor who taught two sections of engineering statistics last term, the first with 25 students and the second with 35, de
Amiraneli [1.4K]

Answer:

a) P=0.1721

b) P=0.3528

c) P=0.3981

Step-by-step explanation:

This sampling can be modeled by a binominal distribution where p is the probability of a project to belong to the first section and q the probability of belonging to the second section.

a) In this case we have a sample size of n=15.

The value of p is p=25/(25+35)=0.4167 and q=1-0.4167=0.5833.

The probability of having exactly 10 projects for the second section is equal to having exactly 5 projects of the first section.

This probability can be calculated as:

P=\frac{n!}{(n-k)!k!}p^kq^{n-k}= \frac{15!}{(10)!5!}\cdot 0.4167^5\cdot0.5833^{10}=0.1721

b) To have at least 10 projects from the 2nd section, means we have at most 5 projects for the first section. In this case, we have to calculate the probability for k=0 (every project belongs to the 2nd section), k=1, k=2, k=3, k=4 and k=5.

We apply the same formula but as a sum:

P(k\leq5)=\sum_{k=0}^{5}\frac{n!}{(n-k)!k!}p^kq^{n-k}

Then we have:

P(k=0)=0.0003\\P(k=1)=0.0033\\P(k=2)=0.0165\\P(k=3)=0.0511\\P(k=4)=0.1095\\P(k=5)=0.1721\\\\P(k\leq5)=0.0003+0.0033+0.0165+0.0511+0.1095+0.1721=0.3528

c) In this case, we have the sum of the probability that k is equal or less than 5, and the probability tha k is 10 or more (10 or more projects belonging to the 1st section).

The first (k less or equal to 5) is already calculated.

We have to calculate for k equal to 10 or more.

P(k\geq10)=\sum_{k=10}^{15}\frac{n!}{(n-k)!k!}p^kq^{n-k}

Then we have

P(k=10)=0.0320\\P(k=11)=0.0104\\P(k=12)=0.0025\\P(k=13)=0.0004\\P(k=14)=0.0000\\P(k=15)=0.0000\\\\P(k\geq10)=0.032+0.0104+0.0025+0.0004+0+0=0.0453

The sum of the probabilities is

P(k\leq5)+P(k\geq10)=0.3528+0.0453=0.3981

8 0
3 years ago
PLS. HELP. ME
klemol [59]

Answer:

C. 1.75

Step-by-step explanation:

7 paved over 4 unpaved

7 divided by 4

1.75

6 0
2 years ago
What is the solution to the linear equation?
DENIUS [597]

x=-5 ___________________

4 0
3 years ago
The ball bearing have volumes of 1.6cm cube and 5.4cm cube . Find the ratio of their surface area.
Scrat [10]

Answer:

64 : 729

Step-by-step explanation:

Ratio of surface area

= (ratio of linear dimensions) ^2

= 1.6^2 : 5.4^2

= 256 : 2916

= 64 : 729

5 0
3 years ago
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