All categories

3 years ago

Please help me this is kinda hard

Mathematics

1 answer:

yuradex [85]3 years ago

7 0

All sides of a square/cube are the same. Since this is a cube, you'll find the volume by "cubing" (get it?) 4.4m.

4.4³ or 4.4 * 4.4 * 4.4 = 85.184m³ but you can round that to 85m³

I hope that helps!

You might be interested in

7 + 79x79x= − 42 Solve this within 5 minutes !

Westkost [7]

42 rhhrhjejrjfitkkrjrjrhrt

3 0

3 years ago

The pass mark for an exam is 92% <br> abbi scored 62 out of 68 <br> does she pass the exam

BartSMP [9]

Answer:

68/100*92= 62.56

No abbi does not pass exam.

7 0

2 years ago

Read 2 more answers

PLEASE HELP!! I’LL GIVE BRAINLIEST!!

lakkis [162]

Answer:

Step-by-step explanation:

[z^4/6²]^-3 = z^-12/6^-6 = 6^6/z^12

6 0

2 years ago

In a game of checkers there are 12 red pieces and 12 black game pieces.Julio is setting up the board to begin playing. what is t

Bond [772]

Since there are equal numbers of pieces, the chances of Julio getting a red on the first pull is 12/24 or 1/2 (reduced)

However on the second pull there are only 11 reds (Julio pulled one out) out of 23 remaining pieces so the chances of pulling the second red are 11/23

Now multiply those possibilities:
1/2 x 11/23 and you will get 11/46 which is the probability of pulling two reds in a row. 11/46 is the answer.

4 0

2 years ago

In an effort to estimate the mean of amount spent per customer for dinner at a major Lawrence restaurant, data were collected fo

larisa86 [58]

Answer:

The 99% confidence interval for the population mean is 22.96 to 26.64

Step-by-step explanation:

Consider the provided information,

A sample of 49 customers. Assume a population standard deviation of $5. If the sample mean is $24.80,

The confidence interval if 99%.

Thus, 1-α=0.99

α=0.01

Now we need to determine $z_{\frac{\alpha}{2}}=z_{0.005}$

Now by using z score table we find that $z_{\frac{\alpha}{2}}=2.58$

The boundaries of the confidence interval are:

$\mu-z_{\frac{\alpha}{2}}\times \frac{\sigma}{\sqrt{n} }\\24.80-2.58\times \frac{5}{\sqrt{49}}=22.96\\\mu+z_{\frac{\alpha}{2}}\times \frac{\sigma}{\sqrt{n} }\\24.80+2.58\times \frac{5}{\sqrt{49}}=26.64$

Hence, the 99% confidence interval for the population mean is 22.96 to 26.64

3 0

3 years ago

Please help me this is kinda hard​

Please help me this is kinda hard