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3 years ago

6

A chemist is looking at an electrically neutral atom that has three valence electrons. If she knows the element is a metalloid,

which one (or ones) is it?

1 answer:

Rus_ich [418]3 years ago

8 0

Your answer is boron,

I looked at the periodic table, there is nothing else that falls under this specs.

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6) (a) Calculate the absorbance of the solution if its concentration is 0.0278 M and its molar extinction coefficient is 35.9 L/

Anvisha [2.4K]

Answer:

6) (a) 0.499; (b) 31.7 %

7) 0.15

Explanation:

6) (a) Absorbance

Beer's Law is

$A = \epsilon cl\\A = \text{35.9 L&\cdot$mol$^{-1}$cm$^{-1}$} $\times$ 0.0278 mol$\cdot$L$^{-1} \times $ 0.5 cm = \mathbf{0.499}$

(b) Percent transmission

$A = \log {\left (\dfrac{1}{T}}\right)}\\\\\%T = 100T\\\\T = \dfrac{\%T}{100}\\\\\dfrac{1}{T} = \dfrac{100 }{\%T}\\\\A = \log \left(\dfrac{100 }{\%T} \right ) = 2 - \log \%T\\\\0.499 = 2 - \log \%T\\\\\log \%T = 2 - 0.499 = 1.501\\\\\%T = 10^{1.501} = \mathbf{31.7}$

7) Absorbance

$A = \log \left (\dfrac{I_{0}}{I} \right ) = \log \left (\dfrac{I_{0}}{0.70I_{0}} \right ) = \log \left (\dfrac{1}{0.70} \right ) = -\log(0.70) = \mathbf{0.15}}$

8 0

3 years ago

What is a paragraph to fit this

german

Answer:

They add carbon Dioxide into the air warming the atmosphere which adds to the greenhouse effect, Making the temperature higher

3 0

3 years ago

Every element has a unique amount of

tamaranim1 [39]

Protons is the answer

5 0

3 years ago

A bowling ball (mass = 7.2 kg, radius = 0.10 m) and a billiard

evablogger [386]

Answer:

Maximum gravitational Force: $F_{gmax} = 1,026*10^{-08} N$

Explanation:

The maximum gravitational force is achieved when the center of gravity are the closer they can be. For the spheres the center of gravity is at the center of it, so the closer this two centers of gravity can be is:

bowling ball radius + billiard ball radius = 0,128 m

The general equation for the magnitude of gravitational force is:

$F_{gmax} = G \frac{M*m}{r_{min}^{2} }$

Solving for:

$G = 6,67*10^{-11} \frac{Nm^{2}}{kg^{2}}$

$M = 7,2 kg$

$m = 0,35 kg$

$r_{min} = 0,128 m$

The result is:

$F_{gmax} = 1,026*10^{-08} N$

3 0

3 years ago

What did ancient astronomers think areas of the moon called mares might be?

RUDIKE [14]

Answer: seas

Explanation:

The ancient astronomers thought the mares on the moon were seas.

7 0

3 years ago