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4 years ago

Please help with number 7!

Mathematics

1 answer:

docker41 [41]4 years ago

8 0

Answer:

He needs at 79

Step-by-step explanation:

He will be taking 6 quizzes.

Let x be the score on the final quiz

The average is found when we add up all the scores and divide by the number of scores

Average = (88+100+95+78+88+x) /6

The average is 88

88 = (88+100+95+78+88+x) /6

Multiply by 6 on each side

88*6 = (88+100+95+78+88+x) /6 *6

528 = (88+100+95+78+88+x)

Combine like terms

528 = 449+x

Subtract 449 from each side

528-429 = 449-449+x

79 =x

He needs at 79

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Can you plzz help me. Evaluate the angles and give reasons for your answer.

Alex777 [14]

Answer:

14. D=70°

e=110°(straight line angles)

15. R=42°(vertically opposite angles)

S=68°(sum of interior angles of a triangle)

16.x=50°(angles on a straight line)

y=70°(sum of interior angles of a triangle)

hope this helps you

8 0

3 years ago

MARK BRAINLIEST AND 12 POINTS

attashe74 [19]

Answer:

125

Step-by-step explanation:

exterior angle is equal to sum of interior opposite angle. so

( 2x + 6 ) + ( 5x ) = ( 8x - 11 )

7x + 6 = 8x - 11

x = 17

exterior angle = ( 8 * 17 ) - 11 = 125

8 0

3 years ago

Read 2 more answers

The recreation center is hiring counselors for summer camp. They need four counselors for every 25 campers. If there are 140 cam

Akimi4 [234]

Jus divide 140 by 25

7 0

3 years ago

Exercise is mixed —some require integration by parts, while others can be integrated by using techniques discussed in the chapte

wlad13 [49]

Answer:

$\frac{2x^{\frac{7}{2}}}{7}+4x+c$

Step-by-step explanation:

We are asked to find the value of the indefinite integral $\int \:x^2\sqrt{x}+4\:dx$ .

Let us solve our given problem applying sum rule as:

$\int \:x^2\sqrt{x}\:dx+\int \:4\:dx$

$\int \:x^2*x^{\frac{1}{2}}\:dx+\int \:4\:dx$

$\int \:x^{\frac{4}{2}}*x^{\frac{1}{2}}\:dx+\int \:4\:dx$

$\int \:x^{\frac{5}{2}}\:dx+\int \:4\:dx$

Now, we will use power rule.

$=\frac{x^{\frac{5}{2}+1}}{\frac{5}{2}+1}}+4x+c$

$=\frac{x^{\frac{7}{2}}}{\frac{7}{2}}+4x+c$

$=\frac{2x^{\frac{7}{2}}}{7}+4x+c$

Therefore, our required integral would be $\frac{2x^{\frac{7}{2}}}{7}+4x+c$ .

7 0

3 years ago

If BC = 4x + 5 and AD = –3x + 26, find AD. A. 3 B. 17 C. 21 D. 31

Keith_Richards [23]

BC must be equal to AD, so 4x+5=-3x+26. You must get all common terms on one side, so 7x=21. then divide to get x alone, and x=3.

6 0

4 years ago