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nataly862011 [7]
3 years ago
8

A student factors 3x2 – 12 to the following. 3(x2 – 4)

Mathematics
2 answers:
prohojiy [21]3 years ago
8 0

Answer:

So, the factors of  3x² – 12  are 3(x-2)(x+2).

Step-by-step explanation:

We have given expression:

3x² – 12

We have to find the factor of the given expression.

First, taking 3 common from the expression we get,

3x² – 12=3(x²-4)

As we know that,

a²-b²= (a-b)(a+b)

Then we get,

3x² – 12= 3(x-2)(x+2)

So, the factors of  3x² – 12  are 3(x-2)(x+2).

kotegsom [21]3 years ago
4 0

Answer:

The expression is equivalent , but is not completely factored

Step-by-step explanation:

A student factors 3x² – 12 to the following. 3(x² – 4)

3x² – 12 is equivalent to 3(x² – 4), because 3 was factored out;

If we multiply by 3 by opening the brackets then we get the same expression 3x² – 12.  

However; <em>3(x² – 4), could be factored further;</em>

<em>To get; 3(x + 2)(x - 2) ; since x² – 4 is a difference of two squares;</em>

<em>Therefore;</em>

<em>3x² – 12 = 3(x² – 4) = 3(x + 2)(x - 2)</em>

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\left[\begin{array}{ccc}s&-1&0\\-1&s&-1\\0&-1&1\end{array}\right]

det(\left[\begin{array}{ccc}s&-1&0\\-1&s&-1\\0&-1&1\end{array}\right])\\\\= s*det(\left[\begin{array}{cc}s&-1\\-1&1\end{array}\right] ) - (-1)*det(\left[\begin{array}{cc}-1&-1\\0&1\end{array}\right] ) + 0*det(\left[\begin{array}{cc}-1&s\\0&-1\end{array}\right] )\\\\= s(s(1)-(-1*-1)) - (-1)(-1*1 - (-1*0)) + 0\\= s(s - 1)) + 1(-1 + 0) \\=s^{2} -s-1

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s^{2} -s-1 =0\\

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