Question

A red die and a blue die are tossed.

Answer 1

Answer:

$P(3,red \ and\ 3, blue)=\frac{1}{36}$

Step-by-step explanation:

-A fair die has 6 faces, a sample space of 6 and each space has a probability of 1/6:

#The probability of 3 in the red die;

$P(3,red)=\frac{1}{6}$

#The probability of 3 in blue die:

$P(3,blue)=\frac{1}{6}$

The probability of a 3 in both dice is the product of the individual probabilities:

$P(3,red and 3, blue)=P(3,red)\times P(3,blue)\\\\=\frac{1}{6}\times \frac{1}{6}\\\\=\frac{1}{36}$

Hence, the probability of a 3 in both dice is $\frac{1}{36}$