These percentages are most likely mass percentages. Therefore, determine the mass of each element in 100g of the compound.
<span>75g C, 25g H. </span>
<span>Divide these masses by their molar mass to find the ratios of the moles of element in the compound. Divide these values by the smallest of the two/three to get the ratios. </span>
<span>6.25:25 C:H --> 1:4 </span>
<span>So the formulae are CH4 (methane).</span>
It describes how, when particles/mc/elements react, despite forming different substances the mass is neither created nor destroyed but only converted.
