Answer:
Cl2 + 2NaBr --> 2NaCl + Br2
Explanation:
This is a single displacement reaction where one side of the ionic compound switches with the other.
So, Cl2 + NaBr ---> NaCl + Br2
This isolates the Bromine and puts the Chlorine in it's place.
Then, balance out the equation like so and you should get
Cl2 + 2NaBr --> 2NaCl + Br2
3Mg + N₂= Mg₃N₂
n(Mg)=12,2g÷24,4g/mol=0,5mol-limiting reagentn
(N₂)=5,16g÷28g/mol=0,18mol
n(Mg₃N₂):n(Mg)=1:3, n(Mg₃N₂)=0,166mol, m(Mg₃N₂)=0,166·101,2=16,8g.
%(N)= 2·Ar(N)÷Mr(Mg₃N₂) = 2·14÷101,2=27,66%=0,2766
%(Mg) = 3·Ar(Mg)÷Mr(Mg₃N₂)= 3·24,4÷101,2=72,34% or 100% - 27,66%= 72,34%.
Electrons were discovered by cathode ray
A.
16 16 0
N -> O + e
7 8 -1
B.
40 40 0
K -> Ca + e
19 20 -1
Balancing the coefficients means that the number of atoms are the same on each side which means that the masses of reactants and products are equal.
Hope this helps :))
