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beks73 [17]
4 years ago
12

Which 1.0 M solution has the lowest pH?  A -HCN  B -H3PO4  C -H2C2O4 D -HCl

Chemistry
2 answers:
fredd [130]4 years ago
8 0
The solution with the lowest pH would mean that it is an acid, specifically a strong acid which completely dissociates into ions in aqueous solution. Among the choices listed above, I think the correct answer is option D. It is nitric acid that will have the lowest pH because it is the only strong acid in the group
ipn [44]4 years ago
3 0

Answer:The correct answer is option D.

Explanation:

Out of these four acids the strongest acid is hydrochloric acid which completely dissociates inits aqueous solution.Where as other acids are weak acid do not dissociates complete in their aqueous solution.

HCl(aq)\rightarrow H^+(aq)+Cl^-(aq)

0.1 M of HCl will form 0.1 M of H^+ ions.

The pH is given as:

pH=-\log[H^+]=-\log[0.1]=1

Hence,the correct answer is option D.

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When a beta particle is released from the nucleus of an atom:
Anon25 [30]
When a beta particle<span> is emitted from the </span>nucleus<span> the </span>nucleus<span> has one more proton and one less neutron. This means the </span>atomic<span> mass number remains unchanged and the </span>atomic<span> number increases by 1.
Best answer :
</span><span>b. the number of electrons in the atom increases by one as the beta particle leaves the nucleus and joins the valence electrons</span>
6 0
3 years ago
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Suppose a piece of silver jewelry contains 7.49x10^22 atoms of silver (Ag). how many moles of silver are in the jewelry?​
zalisa [80]

Answer:

0.124 mol Ag

General Formulas and Concepts:

<u>Atomic Structure</u>

  • Moles

<u>Stoichiometry</u>

  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

[Given] 7.49 × 10²² atoms Ag

[Solve] mol Ag

<u>Step 2: Identify Conversions</u>

Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                    \displaystyle 7.49 \cdot 10^{22} \ atoms \ Ag(\frac{1 \ mol \ Ag}{6.022 \cdot 10^{23} \ atoms \ Ag})
  2. [DA] Divide [Cancel out units]:                                                                       \displaystyle 0.124377 \ mol \ Ag

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

0.124377 mol Ag ≈ 0.124 mol Ag

Topic: AP Chemistry

8 0
3 years ago
What is an advantage of series circuits?
Zanzabum

The answer you are looking for is A: Adding more batteries will increase the current

Since you have a circuit in series, that means that all of the bulbs would be connected to one wire. If you were add more batteries to that <em>one </em>wire, you would end up with a greater flow of energy throughout the bulbs/wire

4 0
4 years ago
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Which change of phase is endothermic chem test.
nikdorinn [45]

Answer:

Melting is an example of an endothermic change.

Explanation:

This is because the system absorbs (heat) energy from the surroundings to increase its temperature.

5 0
2 years ago
2.00 L of 0.800 M NaNO3 must be prepared from a solution known to be 2.50 M in concentration.How many mL are required? Plus don'
Morgarella [4.7K]

Answer:

1.36 × 10³ mL of water.

Explanation:

We can utilize the dilution equation. Recall that:

\displaystyle M_1V_1= M_2V_2

Where <em>M</em> represents molarity and <em>V</em> represents volume.

Let the initial concentration and unknown volume be <em>M</em>₁ and <em>V</em>₁, respectively. Let the final concentration and required volume be <em>M</em>₂ and <em>V</em>₂, respectively. Solve for <em>V</em>₁:

\displaystyle \begin{aligned} (2.50\text{ M})V_1 &= (0.800\text{ M})(2.00\text{ L}) \\ \\ V_1 & = 0.640\text{ L} \end{aligned}

Therefore, we can begin with 0.640 L of the 2.50 M solution and add enough distilled water to dilute the solution to 2.00 L. The required amount of water is thus:
\displaystyle 2.00\text{ L} - 0.640\text{ L} = 1.36\text{ L}

Convert this value to mL:
\displaystyle 1.36\text{ L} \cdot \frac{1000\text{ mL}}{1\text{ L}} = 1.36\times 10^3\text{ mL}

Therefore, about 1.36 × 10³ mL of water need to be added to the 2.50 M solution.

8 0
2 years ago
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