When a beta particle<span> is emitted from the </span>nucleus<span> the </span>nucleus<span> has one more proton and one less neutron. This means the </span>atomic<span> mass number remains unchanged and the </span>atomic<span> number increases by 1.
Best answer :
</span><span>b. the number of electrons in the atom increases by one as the beta particle leaves the nucleus and joins the valence electrons</span>
Answer:
0.124 mol Ag
General Formulas and Concepts:
<u>Atomic Structure</u>
<u>Stoichiometry</u>
- Using Dimensional Analysis
Explanation:
<u>Step 1: Define</u>
[Given] 7.49 × 10²² atoms Ag
[Solve] mol Ag
<u>Step 2: Identify Conversions</u>
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<u>Step 3: Convert</u>
- [DA] Set up:

- [DA] Divide [Cancel out units]:

<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
0.124377 mol Ag ≈ 0.124 mol Ag
Topic: AP Chemistry
The answer you are looking for is A: Adding more batteries will increase the current
Since you have a circuit in series, that means that all of the bulbs would be connected to one wire. If you were add more batteries to that <em>one </em>wire, you would end up with a greater flow of energy throughout the bulbs/wire
Answer:
Melting is an example of an endothermic change.
Explanation:
This is because the system absorbs (heat) energy from the surroundings to increase its temperature.
Answer:
1.36 × 10³ mL of water.
Explanation:
We can utilize the dilution equation. Recall that:

Where <em>M</em> represents molarity and <em>V</em> represents volume.
Let the initial concentration and unknown volume be <em>M</em>₁ and <em>V</em>₁, respectively. Let the final concentration and required volume be <em>M</em>₂ and <em>V</em>₂, respectively. Solve for <em>V</em>₁:

Therefore, we can begin with 0.640 L of the 2.50 M solution and add enough distilled water to dilute the solution to 2.00 L. The required amount of water is thus:

Convert this value to mL:

Therefore, about 1.36 × 10³ mL of water need to be added to the 2.50 M solution.