Answer:
2994 kJ
Explanation:
When one mol of ethane (C₂H₆) is combusted, 1451 kJ of heat is exchanged.
First we convert 61.9 g of C₂H₆ into moles, using its molar mass:
- 61.9 g ÷ 30 g/mol = 2.06 mol C₂H₆
Finally we <u>calculate how much heat is exchanged by the combustion of 2.06 moles of C₂H₆</u>:
- 2.06 mol * 1451 kJ/mol = 2994 kJ
Answer:
1.008moles of iodine
Explanation:
Hello,
This question requires us to calculate the theoretical yield of I₂ or number of moles that reacted.
Percent yield = (actual yield / estimated yield) × 100
Actual yield = 1.2moles
Estimated yield = ?
Percentage yield = 84%
84 / 100 = 1.2 / x
Cross multiply and solve for x
100x = 84 × 1.2
100x = 100.8
x = 100.8/100
x = 1.008moles
1.008 moles of I₂ reacted in excess of H₂ to give 1.2 moles of HI
You can not see between opaque materials because light cannot pass through them.
2x 6.022x10^23= 1.204x10^24
The second and first one but if it isn’t 2 choices then 1
