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eduard
3 years ago
4

1+4=5 2+5=12 3+6=21 8+11=?

Mathematics
1 answer:
Ad libitum [116K]3 years ago
3 0
If you would like to solve this expression, you can calculate this using the following steps:<span>

1 + 4 = 5
2 + 5 = 12
3 + 6 = 21
4 + 7 = 32
5 + 8 = 45
6 + 9 = 60
7 + 10 = 77
8 + 11 = 96

The correct result would be<span> 8 + 11 = 96</span>.</span>
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Karen's Coffee Shop makes a blend that is a mixture of two types of coffee. Type A coffee costs Karen $5.80 per pound, and type
Elina [12.6K]

Answer:

76

Step-by-step explanation:

A + B = 127

5.80A + 4.25B = 657.55

Solve with substitution.

5.80A + 4.25(127 − A) = 657.55

5.80A + 539.75 − 4.25A = 657.55

1.55A = 117.80

A = 76

8 0
3 years ago
A researcher does a study on knowledge of animals in cat lovers compared to dog lovers. In actuality, dog lovers have a greater
suter [353]

Answer:

This decision is not statistically significant .

Step-by-step explanation:

Hypothesis testing is set up so that you can prove a null hypothesis.  Therefore, when you do not find evidence against the null hypothesis, you fail to reject the null hypothesis or the result is not statistically significant.

6 0
4 years ago
If (fx)=5x, what is f^-1(x)
zysi [14]

Answer:

x/5

Step-by-step explanation:

To get the inverse function you need to leave the x alone and then switch variables ( f(x) = y)

f(x) = 5x

y = 5x

y/5 = x

Now that x is alone you switch the x for y and the y for x and you get:

x/5 = y

And this new y is the inverse function of f(x) ( f^-1(x))

f^-1(x) = x/5

6 0
4 years ago
1/6 +3/8 = in simplest form
MrRa [10]
1/6+3/8=13/24 (13/24 is the simplest form in this case)
4 0
4 years ago
In ΔABC, point M is the midpoint of side AB and point D is the midpoint of segment MC. Prove that the area of ΔADC= the area of
Anna11 [10]
A line segment from a vertex to the midpoint of the opposite side is a "median". A median divides the area of the triangle in half, as it divides the base in half without changing the altitude.
AAMC is half AABC. AADC is half AAMC, so is 1/4 of AABC. (By the formula for area of a triangle.)
ABMC is half AABC. ABMD is half ABMC, so is 1/4 of AABC. (By the formula for area of a triangle.)
Then, AADC = 1/4 AABC = ABMC, so AADC = ABMC by the transitive property of equality.
8 0
3 years ago
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