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madam [21]
3 years ago
6

(a) 4.12 x 10^15 atoms U

Chemistry
1 answer:
DochEvi [55]3 years ago
8 0

Answer:

1.63ₓ10⁻⁶ g of U

139.03 g of H

0.385 g of O

141.8 g of Pb

Explanation:

In first place, we need to convert the number of atoms to moles, as we know that 1 mol of anything occupies 6.02×10²³ particles

Therefore:

4.12×10¹⁵ atoms of U . 1 mol / 6.02×10²³ atoms = 6.84×10⁻⁹ moles of U

8.37×10²⁵ atoms of H . 1 mol /6.02×10²³ atoms = 139.03 moles of H

1.45×10²² atoms of O . 1 mol /6.02×10²³ atoms = 0.0241 moles of O

4.12×10²³ atoms of Pb . 1 mol /6.02×10²³ atoms = 0.684 moles of Pb

Moles . Molar mass = Mass (g)

6.84×10⁻⁹ moles of U . 238.03 g/mol = 1.63ₓ10⁻⁶ g of U

139.03 moles of H . 1 g/mol = 139.03 g of H

0.0241 moles of O . 16 g/mol = 0.385 g of O

0.684 moles of Pb . 207.2 g/mol = 141.8 g of Pb

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Identify the limiting reactant when 7.81 g of HCl reacts with 5.24 g of NaOH to produce NaCl and H2O
elena55 [62]

Answer:

NaOH is limiting

Explanation:

                                 Hcl   +    NaOH   ------------      Nacl   + H2O  

Given                     7.81g        5.24g

mol weights           1+35.5     23+16+1

                                 36.5            40

No of Moles        7.81/36.5       5.24/40  

                             0.2139              0.131

No of moles = weight/ molecular weight

No of moles of NaOH is  lower so it is limiting as according to equation one mole of Hcl requires mole of NaOH so equal number of moles are required. NaOH is 0.131 which is far lower than 0.2139

-------- represents arrow in forward direction in equation

7 0
3 years ago
Write the equation of the mirror line for the segment with endpoints (5, 4) and (-1, -1).
charle [14.2K]

Answer:

Explanation:

{\displaystyle {}^{n}x}{}^{n}x, for n = 2, 3, 4, …, showing convergence to the infinitely iterated exponential between the two dots

In mathematics, tetration (or hyper-4) is an operation based on iterated, or repeated, exponentiation. It is the next hyperoperation after exponentiation, but before pentation. The word was coined by Reuben Louis Goodstein from tetra- (four) and iteration.

Under the definition as repeated exponentiation, the notation {\displaystyle {^{n}a}}{\displaystyle {^{n}a}} means {\displaystyle {a^{a^{\cdot ^{\cdot ^{a}}}}}}{\displaystyle {a^{a^{\cdot ^{\cdot ^{a}}}}}}, where n copies of a are iterated via exponentiation, right-to-left, I.e. the application of exponentiation {\displaystyle n-1}n-1 times. n is called the "height" of the function, while a is called the "base," analogous to exponentiation. It would be read as "the nth tetration of a".

Tetration is also defined recursively as

{\displaystyle {^{n}a}:={\begin{cases}1&{\text{if }}n=0\\a^{\left(^{(n-1)}a\right)}&{\text{if }}n>0\end{cases}}}{\displaystyle {^{n}a}:={\begin{cases}1&{\text{if }}n=0\\a^{\left(^{(n-1)}a\right)}&{\text{if }}n>0\end{cases}}},

allowing for attempts to extend tetration to non-natural numbers suc

6 0
3 years ago
Which elements are part of the halogens group?
larisa [96]
The correct answer is Cl, Br, and F. They are all in the halogens group.
5 0
4 years ago
Type Calculations. Given the balanced equation: 2 Al + 3 H2SO4---> Al2(SO4)3 + 3 H2 Molar mass (g/mol): Al=26.98; H2SO4=98.08
Oxana [17]

Answer:

A.  1.88 mol H₂

B.  182 g Al₂(SO₄)₃

C.  54.8%

Explanation:

2 Al  +  3 H₂SO₄  ⇒  Al₂(SO₄)₃  +  3 H₂

A.  Convert grams of Al to moles.  The molar mass is 26.98 g/mol.

(33.8 g)/(26.98 g/mol) = 1.253 mol Al

Use stoichiometry to convert moles of Al to moles of H₂.  Looking at the equation, you can see that for every 2 mol of Al consumed, 3 moles of H₂ is produced.  Use this relationship.

(1.253 mol Al) × (3 mol H₂)/(2 mol Al) = 1.879 mol H₂

You will produce 1.88 mol of H₂ gas.

B.  Again, use stoichiometry.  For every 3 moles of H₂SO₄ consumed, 1 mole of Al₂(SO₄)₃ is produced.

(1.60 mol H₂SO₄) × (1 mol Al₂(SO₄)₃/3 mol H₂SO₄) = 0.533 mol Al₂(SO₄)₃

Convert moles of Al₂(SO₄)₃ to grams.  The molar mass is 342.15 g/mol.

(0.533 mol) × (342.15 g/mol) = 182.48 g Al₂(SO₄)₃

You will produce 182 g of Al₂(SO₄)₃.

C.  Calculate percent yield by dividing the actual yield by the theoretical yield.  Multiply by 100%.

(100.0/182.48) × 100% = 54.8%

The percent yield is 54.8%.

7 0
3 years ago
Each nucleus of a cell contains:
Jobisdone [24]

Hi there!

<u>Answer</u>:

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Explanation:

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5 0
3 years ago
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