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SOVA2 [1]
3 years ago
9

Multiply out the brackets and simplify: 3(x-2)-4(2x-3)

Mathematics
1 answer:
Fantom [35]3 years ago
3 0

Answer:

-5x+6

Step-by-step explanation:

3(x-2) = 3x-6

-4(2x-3) = -8x+12

(3x-6) + (-8x+12) = -5x+6

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The roots of a quadratic equation ax2+bx+c=0 are 3+sqrt2 and 3−sqrt2. Find the values of b and c assuming that a=1.
slamgirl [31]

Answer:

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Step-by-step explanation:

we know that

The general equation of a quadratic function in factored form is equal to

y=a(x-x_1)(x-x_2)

where

a is a coefficient of the leading term

x_1 and x_2 are the roots

we have

a=1\\x_1=3+\sqrt{2}\\x_2=3-\sqrt{2}

substitute

y=(1)(x-(3+\sqrt{2}))(x-(3-\sqrt{2}))

Applying the distributive property convert to expanded form

y=x^2-x(3-\sqrt{2})-x(3+\sqrt{2})+(3+\sqrt{2})(3-\sqrt{2})

y=x^2-(3x-x\sqrt{2})-(3x+x\sqrt{2})+(9-2)

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therefore

b=-6\\c=7

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3 years ago
What is the distance between...
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