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3 years ago

Math is not my strongest subject :/

Mathematics

1 answer:

weqwewe [10]3 years ago

4 0

The angles with measures (5x + 4y)º and 74º are congruent because they form a pair of alternate interior angles between the parallel horizontal bars, so

5x + 4y = 74

The other two labeled angles are also congruent because they are corresponding interior angles that occur between the parallel vertical bars, so

20x + 4y = 164

Then

(20x + 4y) - (5x + 4y) = 164 - 74

(20x - 5x) + (4y - 4y) = 90

15x = 90

x = 6

which means

5*6 + 4y = 74

4y = 44

y = 11

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Solve. a-5/a+4 = 5/4 a = 0 a = -1 a = -9 a = -40

Degger [83]

Answer:

-40=a

Step-by-step explanation:

( a-5)/(a+4) = 5/4

Multiply by (a+4) on each side

( a-5)/(a+4) * (a+4) = 5/4 (a+4)

a-5 = 5/4 (a+4)

Multiply by 4 on each side to clear the fractions

4(a-5) = 5/4*4 (a+4)

4(a-5) = 5 (a+4)

Distribute

4a -20 =5a +20

Subtract 4a from each side

4a -4a -20 = 5a-4a +20

-20 =a+20

Subtract 20 from each side

-20-20 =a+20-20

-40=a

5 0

3 years ago

Solve this two-column proof! (25 pts!) I already solved one an two

melamori03 [73]

Answer:

See explanation

Step-by-step explanation:

Statement Reason

1. $WZ\parallel XY$ Given

2. $WX\parallel ZY$ Given

3. $WZ\cong XY$ Parallelogram property (opposite sides are parallel and congruent)

4. $WX\cong ZY$ Parallelogram property (opposite sides are parallel and congruent)

5. $XZ\cong XZ$ Reflexive property

6. $\triangle WXZ\cong \triangle XYZ$ SSS postulate

7 0

4 years ago

a train leaves barcelona at 21.28 and takes 10 hours nad 33 minutes to reach paris calculate the time and the distance from barc

Brilliant_brown [7]

Speed = Distance / Time, therefore, Speed = 827km / 10.55 hrs. I got 10.55 hours because I converted the 33 minutes into hours and got 0.55 and added it to the 10 hours which is given. so the answer would be approx. 78.39 km / h. I rounded it to the nearest 2 decimal places.

7 0

4 years ago

Bradley earned 15$ painting a fence for 2 hours and $30 for pressure washing the patio and deck for 4 hours. Did he earn the sam

NISA [10]

Answer:

yes

Step-by-step explanation:

4 0

3 years ago

Heyo random person scrolling.Please help me?

Ierofanga [76]

Let's do

$\\ \sf\longmapsto 2sin^260cos60tan^245$

$\\ \sf\longmapsto 2\left(\dfrac{\sqrt{3}}{2}\right)^2\times \dfrac{1}{2}\times (1)^2$

$\\ \sf\longmapsto 2\times \dfrac{(\sqrt{3})^2}{2^2}\times \dfrac{1}{2}\times 1$

$\\ \sf\longmapsto \dfrac{3}{2}\times \dfrac{1}{4}$

$\\ \sf\longmapsto \dfrac{3}{4}$

Trigonometric values

$\Large{ \begin{tabular}{|c|c|c|c|c|c|} \cline{1-6} \theta & \sf 0^{\circ} & \sf 30^{\circ} & \sf 45^{\circ} & \sf 60^{\circ} & \sf 90^{\circ} \\ \cline{1-6} $ \sin $ & 0 & $\dfrac{1}{2 }$ & $\dfrac{1}{ \sqrt{2} }$ & $\dfrac{ \sqrt{3}}{2}$ & 1 \\ \cline{1-6} $ \cos $ & 1 & $ \dfrac{ \sqrt{ 3 }}{2} } $ & $ \dfrac{1}{ \sqrt{2} } $ & $ \dfrac{ 1 }{ 2 } $ & 0 \\ \cline{1-6} $ \tan $ & 0 & $ \dfrac{1}{ \sqrt{3} } $ & 1 & $ \sqrt{3} $ & $ \infty $ \\ \cline{1-6} \cot & $ \infty $ &$ \sqrt{3} $ & 1 & $ \dfrac{1}{ \sqrt{3} } $ &0 \\ \cline{1 - 6} \sec & 1 & $ \dfrac{2}{ \sqrt{3}} $ & $ \sqrt{2} $ & 2 & $ \infty $ \\ \cline{1-6} \csc & $ \infty $ & 2 & $ \sqrt{2 } $ & $ \dfrac{ 2 }{ \sqrt{ 3 } } $ & 1 \\ \cline{1 - 6}\end{tabular}}$

6 0

3 years ago