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Lerok [7]
4 years ago
14

How many molecules are there in 21.6 grams of CH4?

Chemistry
1 answer:
crimeas [40]4 years ago
7 0
See attachement for the answer to your question.

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What is the density of a substance with a mass of 1.8 kg and a volume of 0.2 L?
horrorfan [7]

Answer:

<h3>The answer is 9.0 kg/L</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}  \\

From the question

mass = 1.8 kg

volume = 0.2 L

We have

density  =  \frac{1.8}{0.2}  \\

We have the final answer as

<h3>9.0 kg/L</h3>

Hope this helps you

5 0
3 years ago
A 2.241-g sample of nickel reacts with oxygen to form 2.852 g of the metal oxide.
nlexa [21]

Answer:

The empirical formula is = NiO

Explanation:

Given that:- Mass of nickel = 2.241 g

Mass of the oxide formed = 2.852 g

Mass of the oxygen reacted = Mass of the oxide formed - Mass of nickel  = 2.852 g - 2.241 g = 0.611 g

Molar mass of nickel  = 58.6934 g/mol

Moles of nickel = \frac{2.241}{58.6934}\ mol = 0.03818 mol

Molar mass of oxygen  = 15.999 g/mol

Moles of nickel = \frac{0.611}{15.999}\ mol = 0.03818 mol

Taking the simplest ratio for Ni and O as:

0.03818 : 0.03818 = 1 : 1

<u>The empirical formula is = NiO </u>

4 0
3 years ago
I put in a photo, it’s due today please help!
Arisa [49]

Answer:

I'm sorry didn't understand

3 0
3 years ago
nitrogen will react with hydrogen to form the compound ammonia. The compound formed has properties that are different from the e
satela [25.4K]
A chemical reaction must occur for a compound to have different properties.
3 0
3 years ago
Read 2 more answers
40.0L of N₂ gas are in a sealed container at STP.How many moles of N₂ are present?9 mol
Vinvika [58]

Explanation:

We have to find the number of moles of N₂ that are present in a sample that has a volume of 40.0 L at STP.

STP means Standard Conditions of Temperature and Pressure. These conditions are 273.15 K and 1 atm. We know that 1 mol of N₂ will occupy 22.4 L. We can use that ratio to find the answer to our problem.

1 mol of N₂ = 22.4 L

moles of N₂ = 40.0 L * 1 mol/(22.4 L)

moles of N₂ = 1.79 mol

Answer: 1.79 moles of nitrogen are present.

8 0
1 year ago
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