Answer:
1) 72 mole
2)1152 mole
3)256 mole
4) 2890 mole
Explanation:
very important for u
number of mole= given mass/molecular mass
symbolically : n= m/Mm
1) first atomic mass (carbon =12)
n=6gram × 12gram /mole
n=72mole
2) atomic mass (Magnesium =24)
48 gram × 24 gram /mole
n= 1152 mole
3)atomic mass (oxygen = 16×2=32
n= 8 gram × 32 gram/ mole
n= 256mole
4) atomic mass ( Nitrogen =14 , hydrogen = 1×3
14+3=17
n= 170 gram × 17 gram / mole.
n= 2890 mole
Explanation and Answer:
This is an opinion based question and there could be many different responses these are just examples of solution to restore the fishery:
-limiting the season during which lobsters can be caught this allows the population to reproduce itself gradually but maintaining it in control
-limiting the amount of lobster that can be caught therefore again letting the population increase
Correct Answer: Mass of ore that contains 200 g of Ti is
617.28 g.
Reason:
Given: Ore contains 32.4% Ti by mass.
It implies that, 100 g of ore ≡ 32.4 g of Ti
Therefore, x g of ore ≡ 200 g of Ti
Thus, x =
Hence, mass of ore that contains 200 g of Ti is
617.28 g.
Answer:
CHOOH (aq) + H₂O (l) ⇄ HCOO⁻ (aq) + H₃O⁺ (aq)
Weak acid Base Conj. strong base Conj. acid
H₂S (aq) + NH₃ (aq) ⇄ NH₄⁺(aq) + HS⁻ (aq)
Weak acid Weak Base Conj. strong acid Conj. strong base
Explanation:
To determine the acid-base pairs in the example below we follow the Brownsted Lowry theory.
An acid releases protons
A base accepts protons
CHOOH (aq) + H₂O (l) ↔ HCOO⁻ (aq) + H₃O⁺ (aq)
Formic reacts to water in order to produce formate and hydroniums
Formic release a proton → Acid
Formate can accepted the proton → Conjugate base
Water will be the base, because it will acepted the proton, so the hydronium will be the conjugate acid, because it will release the proton to become water again.
H₂S (aq) + NH₃ (aq) ⇄ NH₄⁺(aq) + HS⁻ (aq)
The sulfidric behaves as an acid, it release the proton to ammonia.
The acid sulfide, becomes the base. It can accept the proton for being, H₂S again.
Then the ammonia is the base (it can accept H⁺) and the ammonium is the conjugate acid (it release the H⁺)