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Morgarella [4.7K]
3 years ago
10

What is the density of a substance with a mass of 1.8 kg and a volume of 0.2 L?

Chemistry
1 answer:
horrorfan [7]3 years ago
5 0

Answer:

<h3>The answer is 9.0 kg/L</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}  \\

From the question

mass = 1.8 kg

volume = 0.2 L

We have

density  =  \frac{1.8}{0.2}  \\

We have the final answer as

<h3>9.0 kg/L</h3>

Hope this helps you

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Sayid recorded the temperatures of four substances in a chart. which conclusion is best supported by the data?
balandron [24]
The conclusion best supported by the data can either be high temperature, low temperature, and normal temperature. Since there are diverse substances included in the chart, It is expected to also have diverse temperatures. 
4 0
2 years ago
a flask was filled with SO2 at a partial pressure of 0.409 atm and O2 at a partial pressure of 0.601 atm. The following gas-phas
jarptica [38.1K]

Answer:

The equilibrium partial pressure of O2 is 0.545 atm

Explanation:

Step 1: Data given

Partial pressure of SO2 = 0.409 atm

Partial pressure of O2 = 0.601 atm

At equilibrium, the partial pressure of SO2 was 0.297 atm.

Step 2: The balanced equation

2SO2 + O2 ⇆ 2SO3

Step 3: The initial pressure

pSO2 = 0.409 atm

pO2 = 0.601 atm

pSO3 = 0 atm

Step 4: Calculate the pressure at the equilibrium

pSO2 = 0.409 - 2X atm

pO2 = 0.601 - X atm

pSO3 = 2X

pSO2 = 0.409 - 2X atm = 0.297

 X = 0.056 atm

pO2 = 0.601 - 0.056 = 0.545 atm

pSO3 = 2*0.056 = 0.112 atm

Step 5: Calculate Kp

Kp = (pSO3)²/((pO2)*(pSO2)²)

Kp = (0.112²) / (0.545 * 0.297²)

Kp = 0.261

The equilibrium partial pressure of O2 is 0.545 atm

3 0
3 years ago
Elements that do not have full outer electron shells will donate, share, or take from other atoms. Choose the items that have th
Gnesinka [82]

Answer:

Ok...

Answer: YTH/JYG

Explanation:

AI+ZN+H=YTH

7 0
3 years ago
A sample of n2 effuses in 255 s. how long will the same size sample of cl2 take to effuse?
7nadin3 [17]
For this problem, we use Graham's Effusion Law to find out the rate of effusion of chlorine gas. The formula is as follows:

R₁/R₂ = √(M₂/M₁)

Let 1 be N₂ while 2 be Cl₂

255/R₂ = √(28/70.8)
Solving for R₂,
R₂ = 405.5 s

<em>Thus, it would take 405.5 s to effuse chlorine gas.</em>
4 0
3 years ago
What do the individual spheres represent in the model!
Trava [24]

Answer:

the individual atom in the molecule

Explanation:

In chemistry, the ball-and-stick model is a molecular model of a chemical substance.  Invidual spheres there represent atoms in the molecule. The bigger atomic number the atom has, the larger diameter of the spheres this atom has in this model.

I hope this answer will help you. Have a nice day !

5 0
2 years ago
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