Here, given-
homozygous alleles 'a' have a frequency of 0.3.
Also the alleles are in equilibrium in a Hardy-Weinberg population. The frequency of individuals that are homozygous for this allele are= 0.49.
The Hardy-Weinberg equilibrium can be defined as the principle which states that the variation in the genetic makeup of a population remains constant and unchanged till there are no external interferences, influencing the population.
Calculation-
Then to find the frequency of the individuals homozygous for this allele the following formula needs to be used-
Thus, the individuals homozygous for the allele can be calculated by
Learn more about the Hardy-Weinberg equilibrium here-
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Transcription is the synthesis RNA from a DNA template where the code in the DNA is converted into a complementary RNA code. Translation is the synthesis of a protein from an MRNA template where the code in the mRNA is converted into an amino acid sequence in a protein.
Answer:
The frequency of the genotype MN, F(MN) = 0.4
Explanation:
Due to technical problems, you will find the complete answer and explanation in the attached files.