Answer:
The question lacks options, the options are:
parents?
A.100% red/white-feather chickens.
B.50% white-feather chickens and 50% red/white-feather chickens.
C.33% white-feather chickens, 33% red-feather chickens, and 33% red/white-feather chickens.
D.25% white-feather chickens, 25% red-feather chickens, and 50% red/white-feather chickens
The Correct answer is D
Explanation:
According to the question, the hybrid chicken has a mixture of red and white feather phenotypes expressed at the same time. This tells us that the red and white alleles are CODOMINANT in the chicken i.e. none is dominant or recessive over the other.
Let's assume that (R) allele is the red feather colour while (r) allele is for white feather colour. Therefore, the red/white feathered chicken will have a Rr genotype. In a cross between two red/white feathered chicken (Rr), the following offsprings will be produced RR, Rr, Rr and rr
RR- Homozygous red feather d chicken (1/4 × 100=25%)
Rr- Hybrid Red/White feathered chicken (2/4 × 100=50%)
rr- Homozygous white feathered chicken (1/4 × 100=25%)
The chromosomes in the sex cells would be half the chromosomes in the body cells; so since each body cell has 40 <span>chromosomes and half of that is 20, there's your answer. It's B. 20</span>
A large glucose molecule requires facilitated diffusion but an oxygen molecule <span>does not is a semipermeable membrane.</span>
