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KatRina [158]
3 years ago
15

T/F The outer planets have solid surfaces that are very rocky and dense

Physics
1 answer:
Luba_88 [7]3 years ago
6 0

Answer:

False

Explanation:

the inner planets have solid rocky dense surfaces

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Guys what's is the meaning of aspects<br>​
shtirl [24]

Answer:

It is the way you see someone or something

8 0
3 years ago
TRUE OR FALSE. if an object does not change its position at a given time interval, then it is at rest or its speed is zero or no
Andrew [12]

Answer:

true

Explanation:

a body can only be accelerating and have speed if it's in motion

3 0
3 years ago
What velocity in km/hr would it take to accelerate a 2 kg object to the same momentum of a 1500 kg object with a velocity of 1.6
Lynna [10]

Answer:

v = 4374 Km/h

Explanation:

Given that,

Mass of the smaller object, m = 2 Kg

Mass of the bigger object, M = 1500 Kg

Velocity of the bigger object, V = 1.62 m/s

Velocity of the smaller object, v = ?

The product of its mass and velocity of a body is equal to its linear momentum. It is given by the formula

                                p = mv  Kg m/s

To find the momentum of the bigger object, substitute M and V in the above equation

                                p = 1500 Kg x 1.62 m/s

                                   = 2430 Kg m/s

The velocity imparted to the small body to attain this momentum is given by the relation

                               v = p/m  m/s

                                   = 2430 Kg m/s  /  2 Kg

                                   = 1215 m/s

By converting the velocity to Km/h

                                v = 4374 km/h

Hence, the velocity of the 2 Kg object is v = 4374 km/h

6 0
3 years ago
Which type of mirror causes beams of light to spread apart
Serggg [28]
Answer: is C
Expiation: you can find the answer on quizlet and it’s diverging mirror so the answer is C
4 0
4 years ago
A car is being tested for safety by colliding it with a brick wall.The 1300 kg car is initially driving towards the wall at a sp
serg [7]

Answer:

44200 N

Explanation:

To calculate the average force exerted on the car, we will use the following equation

\begin{gathered} Ft=\Delta p \\ Ft=m(v_f-v_i) \end{gathered}

Where F is the average force, t is the time, m is the mass, vf is the final velocity and vi is the initial velocity of the car.

Replacing t = 0.5s, m = 1300 kg, vf = -2 m/s, and vi = 15 m/s and solving for F, we get

\begin{gathered} F(0.5s)=(1300\text{ kg\rparen\lparen-2 m/s - 15 m/s\rparen} \\ F(0.5s)=(1300\text{ kg\rparen\lparen-17 m/s\rparen} \\ F(0.5s)=-22100\text{ kg m/s} \\ F=\frac{-22100\text{ kg m/s}}{0.5\text{ s}} \\ F=-44200\text{ N} \end{gathered}

Therefore, the average force exerted on the car by the wall was 44200 N

4 0
1 year ago
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