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2 years ago

Determine whether the underlined numerical value is a parameter or a statistic. explain your reasoning. a certain zoo

Physics

1 answer:

irinina [24]2 years ago

6 0

Parameter, because the data set of all 843 animals in a zoo is a population.

The population of all animals in the Zoo is 843

Proportion = 8%, which is the ratio regarding the population. So 8% is populaton proporiton, i..e Parameter .

A zoo, short for the zoological garden, is a place where animals are kept in enclosures, cared for, presented to the public, and occasionally bred for conservation efforts. The phrase zoological garden refers to zoology, the study of animals. It is also used to refer to an animal park or menagerie. In the United States alone, over 181 million people visit zoos every year. The goal of the modern zoo, which first appeared in the 19th century in the United Kingdom was to entertain and inspire the public by offering scientific inquiry and later educational exhibits. The London Zoological Gardens, which was opened to the public in 1847 after being opened for scientific study in 1828, is where the abbreviation "zoo" first appeared.

To learn more about the Zoo, visit:

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The driver accelerates a 330.0 kg snowmobile, which results in a force being exerted that speeds up the snowmobile from 6.00 m/s

just olya [345]

Answer:

(a) 5610 kgm/s

(b) 5610 Ns.

(c) 78. 64 N

Explanation:

a. Change in momentum: This can be defined as the product of the mass of a body to its change in velocity. The S.I unit of change in momentum is kgm/s.

Mathematically, change in momentum is expressed as

ΔM = mΔv......................... Equation 1

Where ΔM = change in momentum, m = mass of snowmobile, Δv = change in velocity.

Given: m = 330 kg, Δv = v₂-v₁ = 23-6 = 17 m/s.

Note: v₁ and v₂ are the initial and the final velocity of the snowmobile.

ΔM = 330(17)

ΔM = 5610 kgm/s.

(b) Impulse: This can be defined as the product and force and time. The S.I unit of impulse is Ns.

Note: From Newton's second law of motion, impulse is equal to change in momentum.

Therefore,

I = ΔM................ Equation 2

Where I = impulse of the force.

Since ΔM = 5610 kgm/s.

Therefore

I = 5610 Ns.

Thus the impulse = 5610 Ns.

(c) Force: This can be defined as the product of the mass of a body and its acceleration. The S.I unit of force is Newton (N).

F = ma ................................. Equation 3

F = force, m = mass of the body, a = acceleration

But,

a = ( v₂-v₁)/t

Where v₂ = 23.0 m/s, v₁ = 6.0 m/s t = 60.0 s.

a = (23-6)/60

a = 0.283 m/s².

Substituting the value a and m into equation 3

F = 330(0.2383)

F = 78.639 N.

F ≈ 78. 64 N

8 0

3 years ago

How condensation affects the temperature of the area where liquids forms

NISA [10]

Condensation does not effect the temperature of the area, condensation is the product the temperature difference between an object and the area it is in

7 0

3 years ago

Find the equivalent resistance of this parallel circuit with two strands.

svlad2 [7]

In a parallel circuit, the total resistance calculated from the individual resistances is computed from the formula: 1/Rt = 1/R1 + 1/R2. substituting R1 and R2, then
1/Rt = 1/7 + 1/49
1/Rt = 1/6.125 = 1/ 49/8
Rt = 49/8 <span>Ω

The total resistance hence is </span>49/8 Ω

6 0

3 years ago

Two 20kg spheres are placed with their

Maslowich

Answer:

F = 1.07 x 10⁻⁷ N

Explanation:

The gravitational force of attraction between two objects can be found by the use of Newton's Gravitational Law:

$F = \frac{Gm_{1}m_{2}}{r^2}\\\\$

where,

F = Gravitational Force of attraction = ?

G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²

m₁ = m₂ = mass of spheres = 20 kg

r = distance between the objects = 50 cm = 0.5 m

Therefore,

$F = \frac{(6.67\ x\ 10^{-11}\ N.m^2/kg^2)(20\ kg)(20\ kg)}{(0.5\ m)^2}\\\\$

5 0

3 years ago

A metal rod has a length of 123. cm at 200°C. At what temperature will the length be 92.6 cm if the coefficient of linear expans

mestny [16]

Answer:

$\theta_{2} = 15400^0 C$

Explanation:

The formula for linear expansivity, $\alpha = \frac{l_{2} - l_{1} }{l_{1} ( \theta_{2} - \theta_{1} )}$

original length, l₁ = 123 cm = 1.23 m

final length, l₁ = 92.6 cm =0.926 m

original temperature, θ₁ = 200°C

Linear expansivity, α = 2 * 10⁻⁵ °C⁻¹

Putting these values into the formula:

$2 * 10^{-5} = \frac{1.23 - 0.926 }{l_{1} ( \theta_{2} -200 )}\\ \theta_{2} -200 = \frac{0.304}{2 * 10^{-5} } \\\theta_{2} = 15200 + 200\\\theta_{2} = 15400^0 C$

7 0

3 years ago