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3 years ago

8

Pleaseee someone help me in this question ihave bben eating for half an hour and no one helped me.

1 answer:

pav-90 [236]3 years ago

8 0

Cross Multiply by 'x - 5'
Hence
y(x - 5) = 4 -3x
xy - 5y = 4 - 3x

Move all the terms containing an 'x' to one side of the equals and all the others to the opposite side.
xy + 3x = 4 + 5y
Factor out 'x'
x(y + 3) = 4 + 5y
'Cross' divide by 'y + 3'
x = ( 4 + 5y) / (y + 3 )

'x' is now the subject.

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What is the value of K?

sladkih [1.3K]

Answer: its A

Step-by-step explanation:

Because

3 0

3 years ago

Suppose that the Celsius temperature at the point (x, y) in the xy-plane is T(x, y) = x sin 2y and that distance in the xy-plane

liraira [26]

Missing information:

How fast is the temperature experienced by the particle changing in degrees Celsius per meter at the point

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

Answer:

$Rate = 0.935042^\circ /cm$

Step-by-step explanation:

Given

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

$T(x,y) =x\sin2y$

$r = 1m$

$v = 2m/s$

Express the given point P as a unit tangent vector:

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

$u = \frac{\sqrt 3}{2}i - \frac{1}{2}j$

Next, find the gradient of P and T using: $\triangle T = \nabla T * u$

Where

$\nabla T|_{(\frac{1}{2}, \frac{\sqrt 3}{2})} = (sin \sqrt 3)i + (cos \sqrt 3)j$

So: the gradient becomes:

$\triangle T = \nabla T * u$

$\triangle T = [(sin \sqrt 3)i + (cos \sqrt 3)j] * [\frac{\sqrt 3}{2}i - \frac{1}{2}j]$

By vector multiplication, we have:

$\triangle T = (sin \sqrt 3)* \frac{\sqrt 3}{2} - (cos \sqrt 3) \frac{1}{2}$

$\triangle T = 0.9870 * 0.8660 - (-0.1606 * 0.5)$

$\triangle T = 0.9870 * 0.8660 +0.1606 * 0.5$

$\triangle T = 0.935042$

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$Rate = \triangle T = 0.935042^\circ /cm$

3 0

3 years ago

Please could someone help with this one . Thanks I will brainlist

inessss [21]

The answer to this is the third option choice: Reaches a maximum height of 549 after 5.75 seconds.

5 0

4 years ago

Read 2 more answers

Given a dilation around the origin, what is the scale factor K?<br><br> Do, K = (20,16) → (-5,-4)

Rudik [331]

Answer:

Scale factor, K = -1/4

Step-by-step explanation:

Dilation of any image changes its size and the shape remains same.

The scale factor is the ratio of dilated image to original image.

Dilation rule: (x, y) → (kx, ky), where k is the scale factor.

It means k = x₂/x₁ or y₂/y₁

K = -5/20 = -1/4 or K = -4/16 = -1/4.

<u>The negative value of scale factor (K) indicates dilations with 180 degree rotation of the dilated image.</u>

Hence the scale factor is K = -1/4.

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3 years ago

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kolbaska11 [484]

Answer:

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3 years ago