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2 years ago

9

If a store advertised a sale that gave costumers a 1/4 discount, what is the fractions part of the original price that the the c

ostumer will pay?

1 answer:

oee [108]2 years ago

8 0

$\frac{3}{4}$

the original price = 1 = $\frac{1}{4}$ + $\frac{3}{4}$

the customer obtains a $\frac{1}{4}$ discount

and has to pay $\frac{3}{4}$ of the original price

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PLZ HELP FIND R AND EXPLAIN

4vir4ik [10]

Answer:

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Step-by-step explanation:

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3 years ago

A cylinder has a radius of 8 cm and a height of 14 cm.<br><br> What is the volume of the cylinder?

sdas [7]

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2 years ago

Which two types of income does a person in a full-time sales job usually receive?

katovenus [111]

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2 years ago

Read 2 more answers

Find (fºg)(1)<br> f(x) = x² - 1<br> g(x) = √x <br> A.0<br> B.1<br> C.4 √2<br> D. √8

Savatey [412]

Given:

The function are

$f(x)=x^2-1$

$g(x)=\sqrt{x}$

To find:

The value of $(f\circ g)(1)$ .

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We have,

$f(x)=x^2-1$

$g(x)=\sqrt{x}$

We need to find the value of $(f\circ g)(1)$ .

$(f\circ g)(1)=f(g(1))$ $[\because (f\circ g)(x)=f(g(x))]$

$(f\circ g)(1)=f(\sqrt{1})$ $[\because g(x)=\sqrt{x}]$

$(f\circ g)(1)=f(1)$

$(f\circ g)(1)=(1)^2-1$ $[\because f(x)=x^2-1]$

$(f\circ g)(1)=1-1$

$(f\circ g)(1)=0$

The value of $(f\circ g)(1)$ is 0.

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2 years ago

How do I solve this?

grigory [225]

Answer:

x° = 54.5°

Step-by-step explanation:

The measure of angle x is half the difference of the intercepted arcs. The larger arc is shown as 141°. The smaller one must be computed from the arcs shown:

360° -187° -141° = 32°

So, the measure of x° is ...

x° = (141° -32°)/2

x° = 54.5°

6 0

2 years ago