Answer:
7.89 g
Explanation:
Step 1: Write the balanced equation
S₈ + 16 F₂(g) → 8 SF₄
Step 2: Calculate the moles corresponding to 2.34 g of S₈
The molar mass of S₈ is 256.52 g/mol.
Step 3: Calculate the moles of SF₄ produced from 9.12 × 10⁻³ mol of S₈
The molar ratio of S₈ to SF₄ is 1:8. The moles of SF₄ produced are 8/1 × 9.12 × 10⁻³ mol = 0.0730 mol
Step 4: Calculate the mass corresponding to 0.0730 moles of SF₄
The molar mass of SF₄ is 108.07 g/mol.
Answer:
FeSO₄ is the Limiting Reactant
Explanation:
3FeSO₄(aq) + 2(NH₄)₃PO₄ (aq) => 3(NH₄)₃PO₄(aq) + Fe₃(PO₄)(s)
315ml(1.25M)FeSO₄ + 405ml(0.95M)(NH₄)₃PO₄
=> 0.315L(1.25M)FeSO₄ + 0.405ml(0.95M)(NH₄)PO₄
=> 0.394mole FeSO₄ + 0.385mole (NH₄)PO₄
Divide by respective coefficient => the smaller value is the Limiting Reactant.
=> 0.394/3 = 0.131 => 0.385/2 = 0.193
Smaller value is associated with FeSO₄
∴the limiting reactant is FeSO₄.
Summery:
1. convert reactant quantities to moles
2. divide reactants by respective coefficients of balanced equation
3. note smaller value after dividing by respective coefficient => Limiting Reactant.
3% = 0.3
.03*540 = 16.2
540-16.2 = 523.8
Meaning 16.2 milliliters alcohol and 523.8 milliliters water. If my math is correct.
Answer:
mass of CO₂ = 5.402 g
Explanation:
At STP, 1 mole of any gas takes up 22.4L of volume
Thus, 1 mole = 22.4 L
1 L = 1 mole ÷ 22.4
Therefore, 2.75 L = 2.75 mole ÷ 22.4 = 0.123 moles
Molecular weight of CO₂ = 44 g/mole
mass of CO₂ = molecular weight * number of moles = 44 g/mole * 0.123 moles
mass of CO₂ = 5.402 g
