Volume=Mass/Density
Please ask if you have any doubts
Answer:
The answer to your question is 2.92 x 10⁻⁶ g
Explanation:
Data
mass of K = ?
atoms of K = 4.50 x 10¹⁶
Process
To answer this question just remember that the atomic mass of any element is equivalent to Avogadro's number.
1.- Look for the atomic number of Potassium
Atomic number = 39.10 g
2.- Use proportions and cross multiplication
39.10 g of K --------------- 6.023 x 10²³ atoms
x ----------------4.50 x 10¹⁶ atoms
x = (4.50 x 10¹⁶ x 39.10) / 6.023 x 10²³
-Simplify
x = 1.7595 x 10¹⁸ / 6.023 x 10²³
-Result
x = 2.92 x 10⁻⁶ g
If nitrogen monoxide (NO) is added to 2SO2(g) + O2(g) → 2SO3(g),
it will react with O2 and decrease the reaction rate by lowering the amount of O2. So the answer is C. NO decreases collisions between the SO2 and O2 molecules.
Ag2Co3 ->2Ag(+) +CO3(2-)
Ksp=(Ag)^2 (Co3(2-)
Concentration of Ag=0.000253m
Concentration of CO3(2-)=0.000127m
Ksp=(0.000253)^2*0.000127
=8.12*e^-12
Moles of Helium = 39.1 moles
ΔT = (38.08 – 0.08) ֯C = 38.00 ֯C
Q = nC ΔT = 39.1 * 20.8 J/ ֯C mol * 38.00 ֯C = 30904.64 J
W
= P * <span>ΔV = 1atm * (948 - 876) L =
122 atmL</span>
1atmL = 101.325 J
W = 122 * 101.325 J = 12361.65 J
ΔE = q + W = (30904.64 + 12361.65) J = 43266.29 J
Answer is 43266.29 J