Well if it loses one electron, then you would have more protons, so I would assume you would have a positive charge :)
Answer:
Option A: 1*10^-5 M HCl has a pH of 5
Explanation:
a) 1.0 * 10^‒5 M HCl
HCl = a strong acid
pH of HCl = -log[H+]
ph of a 10^‒5 M HCl = -log(10^-5) = 5
(b) 1.0 * 10^5 M NaOH
pOH = -log(10^-5) = 5
pH = 14 -5 = 9
(c) A solution containing approximately equal concentrations of hypochlorous acid (HOCl, Ka = 2.9 * 10^‒8) and the dissolved salt of its conjugate base sodium hypochlorite (NaOCl).
pH = pKa + log[NaOCl/HOCl]
Since [NaOCl]/ [HOCl]= 1
pH = pKa +log(1)
pH = pKa
pH = -log(2.9 * 10^-8)
pH = 7.54
(d) A solution containing approximately equal concentrations of potassium hydrogen phthalate (C8H5KO4, Ka = 3.91 * 10^–6) and the dissolved salt of its conjugate base potassium phthalate.
pH = pKa +log[potassium phthalate/C8H5KO4)
Since [potassium phthalate]/[C8H5KO4] = 1
pH = pKa
pH = -log(3.91*10^-6)
pH = 5.41
e) A solution containing approximately equal concentrations of ammonia (Kb = 1.8 * 10^‒5) and the dissolved salt of its conjugate acid ammonium chloride.
pOH = pKb +log[NH4Cl]/[NH3]
Since [NH4Cl]/[NH3] = 1
pOH = pKb
pOH = 4.74
pH = 14-4.74 = 9.26
Answer:
o processo e de metamorfose. As borboletas e outrostipos de insetos.....
Answer:
The answer to your question is 242 ml
Explanation:
Data
HI 0.211 M Volume = x
KMnO₄ 0.354 M Volume = 24 ml
Balanced Chemical reaction
12HI + 2KMnO₄ + 2H₂SO₄ → 6I₂ + Mn₂SO₄ + K₂SO₄ + 8H₂O
Process
1.- Calculate the moles of KMnO₄ 0.354 M in 24 ml
Molarity = moles / volume (L)
moles = Molarity x volume (L)
moles = 0.354 x 0.024
moles = 0.0085
2.- From the balanced chemical reaction we know that HI and KMnO₄ react in the proportion 12 to 2. Then,
12 moles of HI --------------- 2 moles of KMnO₄
x --------------- 0.0085 moles of KMnO₄
x = (0.0085 x 12)/2
x = 0.051 moles of HI
3.- Calculate the milliliters of HI 0.211 M
Molarity = moles/volume
Volume = moles/molarity
Volume = 0.051/0.211
Volume = 0.242 L or Volume = 242 ml
Answer:
<h3>The answer is 103.82 moles</h3>
Explanation:
To find the number of moles in a substance given it's number of entities we use the formula
![n = \frac{N}{L} \\](https://tex.z-dn.net/?f=n%20%3D%20%20%5Cfrac%7BN%7D%7BL%7D%20%20%5C%5C%20)
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have
![n = \frac{6.25 \times {10}^{25} }{6.02 \times {10}^{23} } \\ = 103.82059...](https://tex.z-dn.net/?f=n%20%3D%20%20%5Cfrac%7B6.25%20%5Ctimes%20%20%7B10%7D%5E%7B25%7D%20%7D%7B6.02%20%5Ctimes%20%20%7B10%7D%5E%7B23%7D%20%7D%20%20%5C%5C%20%20%3D%20103.82059...)
We have the final answer as
<h3>103.82 moles</h3>
Hope this helps you