Question

Square root of 2x squared - 7 -1=4

Answer 1

We start with this:

$\sqrt{[tex] 2x^{2}$-7} [/tex]-1=4

Add 1 to both sides to get:

$\sqrt{ 2x^{2}-7}$=5

Now, to get rid of that nasty square root, we square both sides:

$(\sqrt{2x^{2}-7}) ^{2}$ = $5^{2}$

You're left with this:

$2x^{2} -7$ = 25

Add 7 to both sides to get:

$2x^{2}$ = 32

Now square root both sides to get rid of the square on 2x:

$\sqrt{2x^{2} }$ = $\sqrt{32}$

Since 32 isn't a perfect square we're gonna leave it as a square root.
Now divide both sides by 2 and get your answer:

x = $\frac{\sqrt{32}} {2}$

Answer 2

The answer is probably x=3. I am great at math so it should be the answer!